迷宫问题Java版本实现

如下是迷宫问题的求解思路,可以粘贴在Eclipse下执行,请各位同仁指正。

import java.util.Stack;

public class MazePath {
	int maze[][] = new int[10][10];
	
	public MazePath(){
		maze[1][3] = 1; maze[1][7] = 1;
		maze[2][3] = 1; maze[2][7] = 1;
		maze[3][5] = 1; maze[3][6] = 1;
		maze[4][2] = 1; maze[4][3] = 1; maze[4][4] = 1;
		maze[5][4] = 1;
		maze[6][2] = 1; maze[6][6] = 1;
		maze[7][2] = 1; maze[7][3] = 1; maze[7][4] = 1; maze[7][6] = 1; maze[7][7] = 1;
		maze[8][1] = 1;
		
		for (int j = 0; j < 10; j++) {
			maze[0][j] = 1;
			maze[9][j] = 1;
			maze[j][0] = 1;
			maze[j][9] = 1;
		}
		
	}
	
	public void mazePath () {
		Stack stack = new Stack();
		int i = 1, j = 1;
		stack.add(new PosEle(i, j, 1));
		j++;
		PosEle current;
		
		while (!stack.isEmpty()) {
			if ((i == 8 && j == 8)) {
				printStack(stack);
				maze[i][j] = -1;
			}
			if (maze[i][j] == 0) {
				stack.add(new PosEle(i, j, 1));
				maze[i][j] = -1;
				j++;
			} else {
				do  {
					current = (PosEle) stack.pop();
				} while (current.dir == 4 && !stack.isEmpty());
				i = current.i;
				j = current.j;
				if (current.dir < 4) {
					if (current.dir == 1) {
						i++;
					} else if (current.dir == 2) {
						j--;
					} else if (current.dir == 3) {
						i--;
					}
					current.dir++;
					stack.add(current);
				}
			}
		}

	}
	
	void printStack(Stack stack) {
		System.out.println("Print one path");
		for (int i = 0; i < stack.size(); i++) {
			System.out.println(stack.get(i));
		}
	}
	
	public static void main(String[] args) {
		new MazePath().mazePath();
	}

}

class PosEle {
	int i, j;
	int dir = 0;
	
	PosEle (int i, int j, int dir) {
		this.i = i;
		this.j = j;
		this.dir = dir;
	}
	
	public String toString() {
		return i + ", " + j;
	}
	
}

    原文作者:迷宫问题
    原文地址: https://blog.csdn.net/lei_1000/article/details/51872264
    本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
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