顺序栈的操作实现括号匹配问题

#include <stdio.h>
#include <stdlib.h>
//201603041067   孔德露
#define STACKINCREAMENT 10//用来栈的增长 
#define MAXSIZE 100
#define OVERFLOW -2
#define OK 1
#define ERROR 0
typedef int status;
typedef char SElemtype;
typedef struct
{
    SElemtype *base;
    SElemtype *top;
    status stacksize;
}sqstack;
 
//初始化栈
status Init(sqstack *s)
{
    s->base = (SElemtype *)malloc(MAXSIZE* sizeof(SElemtype));
    if(!s->base) 
            exit(OVERFLOW);
    s->top = s->base;
    s->stacksize = MAXSIZE ;
    return OK;
}
 
//获取栈顶元素
status Gettop(sqstack *s, SElemtype e)
{
    if(s->top == s->base) 
            return ERROR;
    e = *(s->top-1);
    return OK;
}
 
//压栈
status push(sqstack *s, SElemtype e)
{
    if(s->top - s->base >= s->stacksize)
    {
      s->base = (SElemtype *)realloc(s->base, (s->stacksize + STACKINCREAMENT) * sizeof(SElemtype));
      if(!s->base)
              exit(OVERFLOW);
      s->top = s->base + s->stacksize;
      s->stacksize += STACKINCREAMENT;
    }
    *s->top++ = e;
    return OK;
}
 
//出栈
status pop(sqstack *s, SElemtype *e)
{
        if(s->top == s->base) 
                return ERROR;
        *e=*--s->top;
        return OK;
}
 
//判断是否为空栈
status stackempty(sqstack *s)
{
        if(s->top==s->base)
            return OK;
        return ERROR;
}
 
//清空栈
status clearstack(sqstack *s)
{
        if(s->top == s->base) 
                return ERROR;
        s->top = s->base;
        return OK;
}
 
//括号匹配算法
status Parenthesis_match(sqstack *s,char *str)
{
        int i=0, flag=0;
        SElemtype e;
        while(str[i]!='\0')
        {
            switch(str[i])
            {
                case '(':
                        push(s,str[i]);
                        break;
                case '[':
                        push(s,str[i]);
                        break;
                case ')':
                        {
                          pop(s,&e);
                          if(e != '(') 
                                  flag=1;
                        }
                        break;
                case ']':
                        {
                          pop(s,&e);
                          if(e!='[')
                                  flag=1;
                        }
                        break;
                default:
                        break;
            }
            if(flag)
                    break;
            i++;
    }
 
   if(!flag && stackempty(s))
        printf("括号匹配成功!");
   else
        printf("括号匹配失败!");
   return OK;
}
 
int main()
{
    char str[100], enter;
    sqstack s;
    Init(&s);
    printf("请输入字符串:");
    scanf("%s",str);
    scanf("%c",&enter);
    Parenthesis_match(&s,str);
    return 0;
}

    原文作者:括号匹配问题
    原文地址: https://blog.csdn.net/VianaKong/article/details/79953739
    本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
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