循环链表--解决约瑟夫环问题

循环链表只是把单链表的最后一个结点指向头结点,本链表增加了一个头结点。

#include <stdio.h>
#include <stdlib.h>

typedef struct Node
{
    int data;
    struct Node *next;
}*Rlist;

int errMemory(Rlist p)
{
    if(p==NULL)
    {
        printf("内存申请失败!\n");
        return 0;
    }else
    {
        return 1;
    }
}

Rlist init(Rlist head) //建立哨兵结点
{
    Rlist p;
    p = (Rlist)malloc(sizeof(struct Node));
    if(errMemory(p))
    {
        head = p;
        p->next =NULL;
        return head;
    }
    return NULL;
}
Rlist createList(Rlist head)
{
    int n,i=1;
    Rlist p,p1;
    p1= head;
    printf("输入数据规模:\n");
    scanf("%d",&n);

    for(i=1;i<=n;i++)
    {
        p=(Rlist)malloc(sizeof(struct Node));
        if(errMemory(p)==0)
        {
            return head;
        }
        p->data = i;
        p1->next = p;
        p->next = head->next;
        p1 = p;
    }
    return head;
}

int Length(Rlist head)
{
    int len=0;
    Rlist p;
    p = head->next;
    if(head->next==NULL)
    {
        len = 0;
    }else
    {
        while(p!=NULL)
        {
            len++;
            p = p->next;
            if(head->next == p )
            {
                break;
            }
        }
    }
    return len;
}

void print(Rlist head)
{
    Rlist p=head->next;
    while(p !=NULL)
    {
        printf("%d ",p->data);
        p=p->next;
        if(p == head->next)
        {
            break;
        }
    }
}

Rlist deletePos(Rlist head,int num)
{
    Rlist h,p=head,p1=NULL;
    int i;
    for(i=1;i<=Length(head);i++)
    {
        h = p;
        p = p->next;
        if(p->data == num)
        {
            if(i==1)
            {
                p1=head->next;
                while(p1!=NULL)
                {
                    if(p1->next==head->next)
                    {
                        break;
                    }
                    p1 = p1->next;
                }
            }
            h->next = p->next;
            if(p1!=NULL)
            {
                p1->next = p->next;
            }
            free(p);
            break;
        }
    }
    return head;
}

int main()
{
    Rlist Head,p,p1;
    int i,m,len;
    Head =init(Head);
    Head = createList(Head);
    print(Head);
    printf("\n");
    printf("输入报数位置:\n");
    scanf("%d",&m);
    p=Head->next;
    printf("出列顺序:\n");
    len = Length(Head);
    while(len-->0)
    {
        for(i=1;i<m;i++)
        {
            p = p->next;
        }
        printf("%d ",p->data);
        p1 = p;
        p=p->next;
        Head = deletePos(Head,p1->data);
    }
    return 0;
}

《循环链表--解决约瑟夫环问题》

    原文作者:约瑟夫环问题
    原文地址: https://blog.csdn.net/hiluo302/article/details/51189457
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