几个简单的数据点平滑处理算法

原:http://blog.csdn.net/liyuanbhu/article/details/11119081

仅供自己学习参考。

几个简单的数据点平滑处理算法

2013-09-05 13:29
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《几个简单的数据点平滑处理算法》 分类: 数值计算
(19)
《几个简单的数据点平滑处理算法》

版权声明:本文为博主原创文章,未经博主允许不得转载。

目录(?)[+]

最近在写一些数据处理的程序。经常需要对数据进行平滑处理。直接用FIR滤波器或IIR滤波器都有一个启动问题,滤波完成后总要对数据掐头去尾。因此去找了些简单的数据平滑处理的方法。

在一本老版本的《数学手册》中找到了几个基于最小二乘法的数据平滑算法。将其写成了C 代码,测试了一下,效果还可以。这里简单的记录一下,算是给自己做个笔记。

算法的原理很简单,以五点三次平滑为例。取相邻的5个数据点,可以拟合出一条3次曲线来,然后用3次曲线上相应的位置的数据值作为滤波后结果。简单的说就是 Savitzky-Golay 滤波器 。只不过Savitzky-Golay 滤波器并不特殊考虑边界的几个数据点,而这个算法还特意把边上的几个点的数据拟合结果给推导了出来。

不多说了,下面贴代码。首先是线性拟合平滑处理的代码. 分别为三点线性平滑、五点线性平滑和七点线性平滑。

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            void 
            
            linearSmooth3 
            
            ( 
            
            double 
            
            in
            
            [], 
            
            double 
            
            out
            
            [], 
            
            int 
            
            N 
            
            )
           
           
           
           
            
            {
             
           
           
           
               
            
            int 
            
            i
            
            ;
           
           
           
               
            
            if 
            
            ( 
            
            N 
            
            < 
            
            3 
            
            )
           
           
           
               
            
            {
             
           
           
           
                   
            
            for 
            
            ( 
            
            i 
            
            = 
            
            0
            
            ; 
            
            i 
            
            <= 
            
            N 
            
            - 
            
            1
            
            ; 
            
            i
            
            ++ 
            
            )
           
           
           
                   
            
            {
             
           
           
           
                       
            
            out
            
            [
            
            i
            
            ] 
            
            = 
            
            in
            
            [
            
            i
            
            ];
           
           
           
                   
            
            }
           
           
           
               
            
            }
           
           
           
               
            
            else
           
           
           
               
            
            {
             
           
           
           
                   
            
            out
            
            [
            
            0
            
            ] 
            
            = 
            
            ( 
            
            5.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            2.0 
            
            * 
            
            in
            
            [
            
            1
            
            ] 
            
            - 
            
            in
            
            [
            
            2
            
            ] 
            
            ) 
            
            / 
            
            6.0
            
            ;
           
           
           
           

           
           
           
                   
            
            for 
            
            ( 
            
            i 
            
            = 
            
            1
            
            ; 
            
            i 
            
            <= 
            
            N 
            
            - 
            
            2
            
            ; 
            
            i
            
            ++ 
            
            )
           
           
           
                   
            
            {
             
           
           
           
                       
            
            out
            
            [
            
            i
            
            ] 
            
            = 
            
            ( 
            
            in
            
            [
            
            i 
            
            - 
            
            1
            
            ] 
            
            + 
            
            in
            
            [
            
            i
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            1
            
            ] 
            
            ) 
            
            / 
            
            3.0
            
            ;
           
           
           
                   
            
            }
           
           
           
           

           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            = 
            
            ( 
            
            5.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            + 
            
            2.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            - 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            ) 
            
            / 
            
            6.0
            
            ;
           
           
           
               
            
            }
           
           
           
           
            
            }
           
           
           
           

           
           
           
           
            
            void 
            
            linearSmooth5 
            
            ( 
            
            double 
            
            in
            
            [], 
            
            double 
            
            out
            
            [], 
            
            int 
            
            N 
            
            )
           
           
           
           
            
            {
             
           
           
           
               
            
            int 
            
            i
            
            ;
           
           
           
               
            
            if 
            
            ( 
            
            N 
            
            < 
            
            5 
            
            )
           
           
           
               
            
            {
             
           
           
           
                   
            
            for 
            
            ( 
            
            i 
            
            = 
            
            0
            
            ; 
            
            i 
            
            <= 
            
            N 
            
            - 
            
            1
            
            ; 
            
            i
            
            ++ 
            
            )
           
           
           
                   
            
            {
             
           
           
           
                       
            
            out
            
            [
            
            i
            
            ] 
            
            = 
            
            in
            
            [
            
            i
            
            ];
           
           
           
                   
            
            }
           
           
           
               
            
            }
           
           
           
               
            
            else
           
           
           
               
            
            {
             
           
           
           
                   
            
            out
            
            [
            
            0
            
            ] 
            
            = 
            
            ( 
            
            3.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            2.0 
            
            * 
            
            in
            
            [
            
            1
            
            ] 
            
            + 
            
            in
            
            [
            
            2
            
            ] 
            
            - 
            
            in
            
            [
            
            4
            
            ] 
            
            ) 
            
            / 
            
            5.0
            
            ;
           
           
           
                   
            
            out
            
            [
            
            1
            
            ] 
            
            = 
            
            ( 
            
            4.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            3.0 
            
            * 
            
            in
            
            [
            
            1
            
            ] 
            
            + 
            
            2 
            
            * 
            
            in
            
            [
            
            2
            
            ] 
            
            + 
            
            in
            
            [
            
            3
            
            ] 
            
            ) 
            
            / 
            
            10.0
            
            ;
           
           
           
                   
            
            for 
            
            ( 
            
            i 
            
            = 
            
            2
            
            ; 
            
            i 
            
            <= 
            
            N 
            
            - 
            
            3
            
            ; 
            
            i
            
            ++ 
            
            )
           
           
           
                   
            
            {
             
           
           
           
                       
            
            out
            
            [
            
            i
            
            ] 
            
            = 
            
            ( 
            
            in
            
            [
            
            i 
            
            - 
            
            2
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            - 
            
            1
            
            ] 
            
            + 
            
            in
            
            [
            
            i
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            1
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            2
            
            ] 
            
            ) 
            
            / 
            
            5.0
            
            ;
           
           
           
                   
            
            }
           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            = 
            
            ( 
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            + 
            
            3.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            + 
            
            2 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            + 
            
            in
            
            [
            
            N 
            
            - 
            
            4
            
            ] 
            
            ) 
            
            / 
            
            10.0
            
            ;
           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            = 
            
            ( 
            
            3.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            + 
            
            2.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            + 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            - 
            
            in
            
            [
            
            N 
            
            - 
            
            5
            
            ] 
            
            ) 
            
            / 
            
            5.0
            
            ;
           
           
           
               
            
            }
           
           
           
           
            
            }
           
           
           
           

           
           
           
           
            
            void 
            
            linearSmooth7 
            
            ( 
            
            double 
            
            in
            
            [], 
            
            double 
            
            out
            
            [], 
            
            int 
            
            N 
            
            )
           
           
           
           
            
            {
             
           
           
           
               
            
            int 
            
            i
            
            ;
           
           
           
               
            
            if 
            
            ( 
            
            N 
            
            < 
            
            7 
            
            )
           
           
           
               
            
            {
             
           
           
           
                   
            
            for 
            
            ( 
            
            i 
            
            = 
            
            0
            
            ; 
            
            i 
            
            <= 
            
            N 
            
            - 
            
            1
            
            ; 
            
            i
            
            ++ 
            
            )
           
           
           
                   
            
            {
             
           
           
           
                       
            
            out
            
            [
            
            i
            
            ] 
            
            = 
            
            in
            
            [
            
            i
            
            ];
           
           
           
                   
            
            }
           
           
           
               
            
            }
           
           
           
               
            
            else
           
           
           
               
            
            {
             
           
           
           
                   
            
            out
            
            [
            
            0
            
            ] 
            
            = 
            
            ( 
            
            13.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            10.0 
            
            * 
            
            in
            
            [
            
            1
            
            ] 
            
            + 
            
            7.0 
            
            * 
            
            in
            
            [
            
            2
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            3
            
            ] 
            
            +
           
           
           
                             
            
            in
            
            [
            
            4
            
            ] 
            
            - 
            
            2.0 
            
            * 
            
            in
            
            [
            
            5
            
            ] 
            
            - 
            
            5.0 
            
            * 
            
            in
            
            [
            
            6
            
            ] 
            
            ) 
            
            / 
            
            28.0
            
            ;
           
           
           
           

           
           
           
                   
            
            out
            
            [
            
            1
            
            ] 
            
            = 
            
            ( 
            
            5.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            1
            
            ] 
            
            + 
            
            3 
            
            * 
            
            in
            
            [
            
            2
            
            ] 
            
            + 
            
            2 
            
            * 
            
            in
            
            [
            
            3
            
            ] 
            
            +
           
           
           
                             
            
            in
            
            [
            
            4
            
            ] 
            
            - 
            
            in
            
            [
            
            6
            
            ] 
            
            ) 
            
            / 
            
            14.0
            
            ;
           
           
           
           

           
           
           
                   
            
            out
            
            [
            
            2
            
            ] 
            
            = 
            
            ( 
            
            7.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            6.0 
            
            * 
            
            in 
            
            [
            
            1
            
            ] 
            
            + 
            
            5.0 
            
            * 
            
            in
            
            [
            
            2
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            3
            
            ] 
            
            +
           
           
           
                             
            
            3.0 
            
            * 
            
            in
            
            [
            
            4
            
            ] 
            
            + 
            
            2.0 
            
            * 
            
            in
            
            [
            
            5
            
            ] 
            
            + 
            
            in
            
            [
            
            6
            
            ] 
            
            ) 
            
            / 
            
            28.0
            
            ;
           
           
           
           

           
           
           
                   
            
            for 
            
            ( 
            
            i 
            
            = 
            
            3
            
            ; 
            
            i 
            
            <= 
            
            N 
            
            - 
            
            4
            
            ; 
            
            i
            
            ++ 
            
            )
           
           
           
                   
            
            {
             
           
           
           
                       
            
            out
            
            [
            
            i
            
            ] 
            
            = 
            
            ( 
            
            in
            
            [
            
            i 
            
            - 
            
            3
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            - 
            
            2
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            - 
            
            1
            
            ] 
            
            + 
            
            in
            
            [
            
            i
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            1
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            2
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            3
            
            ] 
            
            ) 
            
            / 
            
            7.0
            
            ;
           
           
           
                   
            
            }
           
           
           
           

           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            = 
            
            ( 
            
            7.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            + 
            
            6.0 
            
            * 
            
            in 
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            + 
            
            5.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            +
           
           
           
                                 
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            4
            
            ] 
            
            + 
            
            3.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            5
            
            ] 
            
            + 
            
            2.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            6
            
            ] 
            
            + 
            
            in
            
            [
            
            N 
            
            - 
            
            7
            
            ] 
            
            ) 
            
            / 
            
            28.0
            
            ;
           
           
           
           

           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            = 
            
            ( 
            
            5.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            + 
            
            3.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            +
           
           
           
                                 
            
            2.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            4
            
            ] 
            
            + 
            
            in
            
            [
            
            N 
            
            - 
            
            5
            
            ] 
            
            - 
            
            in
            
            [
            
            N 
            
            - 
            
            7
            
            ] 
            
            ) 
            
            / 
            
            14.0
            
            ;
           
           
           
           

           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            = 
            
            ( 
            
            13.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            + 
            
            10.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            + 
            
            7.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            +
           
           
           
                                 
            
            4 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            4
            
            ] 
            
            + 
            
            in
            
            [
            
            N 
            
            - 
            
            5
            
            ] 
            
            - 
            
            2 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            6
            
            ] 
            
            - 
            
            5 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            7
            
            ] 
            
            ) 
            
            / 
            
            28.0
            
            ;
           
           
           
               
            
            }
           
           
           
           
            
            }
           
           
来自CODE的代码片 linearSmooth.c

然后是利用二次函数拟合平滑。

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            void 
            
            quadraticSmooth5
            
            (
            
            double 
            
            in
            
            [], 
            
            double 
            
            out
            
            [], 
            
            int 
            
            N
            
            )
           
           
           
           
            
            {
             
           
           
           
               
            
            int 
            
            i
            
            ;
           
           
           
               
            
            if 
            
            ( 
            
            N 
            
            < 
            
            5 
            
            )
           
           
           
               
            
            {
             
           
           
           
                   
            
            for 
            
            ( 
            
            i 
            
            = 
            
            0
            
            ; 
            
            i 
            
            <= 
            
            N 
            
            - 
            
            1
            
            ; 
            
            i
            
            ++ 
            
            )
           
           
           
                   
            
            {
             
           
           
           
                       
            
            out
            
            [
            
            i
            
            ] 
            
            = 
            
            in
            
            [
            
            i
            
            ];
           
           
           
                   
            
            }
           
           
           
               
            
            }
           
           
           
               
            
            else
           
           
           
               
            
            {
             
           
           
           
                   
            
            out
            
            [
            
            0
            
            ] 
            
            = 
            
            ( 
            
            31.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            9.0 
            
            * 
            
            in
            
            [
            
            1
            
            ] 
            
            - 
            
            3.0 
            
            * 
            
            in
            
            [
            
            2
            
            ] 
            
            - 
            
            5.0 
            
            * 
            
            in
            
            [
            
            3
            
            ] 
            
            + 
            
            3.0 
            
            * 
            
            in
            
            [
            
            4
            
            ] 
            
            ) 
            
            / 
            
            35.0
            
            ;
           
           
           
                   
            
            out
            
            [
            
            1
            
            ] 
            
            = 
            
            ( 
            
            9.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            13.0 
            
            * 
            
            in
            
            [
            
            1
            
            ] 
            
            + 
            
            12 
            
            * 
            
            in
            
            [
            
            2
            
            ] 
            
            + 
            
            6.0 
            
            * 
            
            in
            
            [
            
            3
            
            ] 
            
            - 
            
            5.0 
            
            *
            
            in
            
            [
            
            4
            
            ]) 
            
            / 
            
            35.0
            
            ;
           
           
           
                   
            
            for 
            
            ( 
            
            i 
            
            = 
            
            2
            
            ; 
            
            i 
            
            <= 
            
            N 
            
            - 
            
            3
            
            ; 
            
            i
            
            ++ 
            
            )
           
           
           
                   
            
            {
             
           
           
           
                       
            
            out
            
            [
            
            i
            
            ] 
            
            = 
            
            ( 
            
            - 
            
            3.0 
            
            * 
            
            (
            
            in
            
            [
            
            i 
            
            - 
            
            2
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            2
            
            ]) 
            
            +
           
           
           
                                 
            
            12.0 
            
            * 
            
            (
            
            in
            
            [
            
            i 
            
            - 
            
            1
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            1
            
            ]) 
            
            + 
            
            17 
            
            * 
            
            in
            
            [
            
            i
            
            ] 
            
            ) 
            
            / 
            
            35.0
            
            ;
           
           
           
                   
            
            }
           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            = 
            
            ( 
            
            9.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            + 
            
            13.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            + 
            
            12.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            + 
            
            6.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            4
            
            ] 
            
            - 
            
            5.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            5
            
            ] 
            
            ) 
            
            / 
            
            35.0
            
            ;
           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            = 
            
            ( 
            
            31.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            + 
            
            9.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            - 
            
            3.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            - 
            
            5.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            4
            
            ] 
            
            + 
            
            3.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            5
            
            ]) 
            
            / 
            
            35.0
            
            ;
           
           
           
               
            
            }
           
           
           
           
            
            }
           
           
           
           

           
           
           
           

           
           
           
           
            
            void 
            
            quadraticSmooth7
            
            (
            
            double 
            
            in
            
            [], 
            
            double 
            
            out
            
            [], 
            
            int 
            
            N
            
            )
           
           
           
           
            
            {
             
           
           
           
               
            
            int 
            
            i
            
            ;
           
           
           
               
            
            if 
            
            ( 
            
            N 
            
            < 
            
            7 
            
            )
           
           
           
               
            
            {
             
           
           
           
                   
            
            for 
            
            ( 
            
            i 
            
            = 
            
            0
            
            ; 
            
            i 
            
            <= 
            
            N 
            
            - 
            
            1
            
            ; 
            
            i
            
            ++ 
            
            )
           
           
           
                   
            
            {
             
           
           
           
                       
            
            out
            
            [
            
            i
            
            ] 
            
            = 
            
            in
            
            [
            
            i
            
            ];
           
           
           
                   
            
            }
           
           
           
               
            
            }
           
           
           
               
            
            else
           
           
           
               
            
            {
             
           
           
           
                   
            
            out
            
            [
            
            0
            
            ] 
            
            = 
            
            ( 
            
            32.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            15.0 
            
            * 
            
            in
            
            [
            
            1
            
            ] 
            
            + 
            
            3.0 
            
            * 
            
            in
            
            [
            
            2
            
            ] 
            
            - 
            
            4.0 
            
            * 
            
            in
            
            [
            
            3
            
            ] 
            
            -
           
           
           
                             
            
            6.0 
            
            * 
            
            in
            
            [
            
            4
            
            ] 
            
            - 
            
            3.0 
            
            * 
            
            in
            
            [
            
            5
            
            ] 
            
            + 
            
            5.0 
            
            * 
            
            in
            
            [
            
            6
            
            ] 
            
            ) 
            
            / 
            
            42.0
            
            ;
           
           
           
           

           
           
           
                   
            
            out
            
            [
            
            1
            
            ] 
            
            = 
            
            ( 
            
            5.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            1
            
            ] 
            
            + 
            
            3.0 
            
            * 
            
            in
            
            [
            
            2
            
            ] 
            
            + 
            
            2.0 
            
            * 
            
            in
            
            [
            
            3
            
            ] 
            
            +
           
           
           
                             
            
            in
            
            [
            
            4
            
            ] 
            
            - 
            
            in
            
            [
            
            6
            
            ] 
            
            ) 
            
            / 
            
            14.0
            
            ;
           
           
           
           

           
           
           
                   
            
            out
            
            [
            
            2
            
            ] 
            
            = 
            
            ( 
            
            1.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            3.0 
            
            * 
            
            in 
            
            [
            
            1
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            2
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            3
            
            ] 
            
            +
           
           
           
                             
            
            3.0 
            
            * 
            
            in
            
            [
            
            4
            
            ] 
            
            + 
            
            1.0 
            
            * 
            
            in
            
            [
            
            5
            
            ] 
            
            - 
            
            2.0 
            
            * 
            
            in
            
            [
            
            6
            
            ] 
            
            ) 
            
            / 
            
            14.0
            
            ;
           
           
           
                   
            
            for 
            
            ( 
            
            i 
            
            = 
            
            3
            
            ; 
            
            i 
            
            <= 
            
            N 
            
            - 
            
            4
            
            ; 
            
            i
            
            ++ 
            
            )
           
           
           
                   
            
            {
             
           
           
           
                       
            
            out
            
            [
            
            i
            
            ] 
            
            = 
            
            ( 
            
            -
            
            2.0 
            
            * 
            
            (
            
            in
            
            [
            
            i 
            
            - 
            
            3
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            3
            
            ]) 
            
            +
           
           
           
                                  
            
            3.0 
            
            * 
            
            (
            
            in
            
            [
            
            i 
            
            - 
            
            2
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            2
            
            ]) 
            
            +
           
           
           
                                 
            
            6.0 
            
            * 
            
            (
            
            in
            
            [
            
            i 
            
            - 
            
            1
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            1
            
            ]) 
            
            + 
            
            7.0 
            
            * 
            
            in
            
            [
            
            i
            
            ] 
            
            ) 
            
            / 
            
            21.0
            
            ;
           
           
           
                   
            
            }
           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            = 
            
            ( 
            
            1.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            + 
            
            3.0 
            
            * 
            
            in 
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            +
           
           
           
                                 
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            4
            
            ] 
            
            + 
            
            3.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            5
            
            ] 
            
            + 
            
            1.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            6
            
            ] 
            
            - 
            
            2.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            7
            
            ] 
            
            ) 
            
            / 
            
            14.0
            
            ;
           
           
           
           

           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            = 
            
            ( 
            
            5.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            + 
            
            3.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            +
           
           
           
                                 
            
            2.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            4
            
            ] 
            
            + 
            
            in
            
            [
            
            N 
            
            - 
            
            5
            
            ] 
            
            - 
            
            in
            
            [
            
            N 
            
            - 
            
            7
            
            ] 
            
            ) 
            
            / 
            
            14.0
            
            ;
           
           
           
           

           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            = 
            
            ( 
            
            32.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            + 
            
            15.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            + 
            
            3.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            -
           
           
           
                                 
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            4
            
            ] 
            
            - 
            
            6.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            5
            
            ] 
            
            - 
            
            3.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            6
            
            ] 
            
            + 
            
            5.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            7
            
            ] 
            
            ) 
            
            / 
            
            42.0
            
            ;
           
           
           
               
            
            }
           
           
           
           
            
            }
           
           
来自CODE的代码片 quadraticSmooth.c

最后是三次函数拟合平滑。

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            /**
           
           
           
           
            
             * 五点三次平滑
           
           
           
           
            
             *
           
           
           
           
            
             */
           
           
           
           
            
            void 
            
            cubicSmooth5 
            
            ( 
            
            double 
            
            in
            
            [], 
            
            double 
            
            out
            
            [], 
            
            int 
            
            N 
            
            )
           
           
           
           
            
            {
             
           
           
           
           

           
           
           
               
            
            int 
            
            i
            
            ;
           
           
           
               
            
            if 
            
            ( 
            
            N 
            
            < 
            
            5 
            
            )
           
           
           
               
            
            {
             
           
           
           
                   
            
            for 
            
            ( 
            
            i 
            
            = 
            
            0
            
            ; 
            
            i 
            
            <= 
            
            N 
            
            - 
            
            1
            
            ; 
            
            i
            
            ++ 
            
            )
           
           
           
                       
            
            out
            
            [
            
            i
            
            ] 
            
            = 
            
            in
            
            [
            
            i
            
            ];
           
           
           
               
            
            }
           
           
           
           

           
           
           
               
            
            else
           
           
           
               
            
            {
             
           
           
           
                   
            
            out
            
            [
            
            0
            
            ] 
            
            = 
            
            (
            
            69.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            1
            
            ] 
            
            - 
            
            6.0 
            
            * 
            
            in
            
            [
            
            2
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            3
            
            ] 
            
            - 
            
            in
            
            [
            
            4
            
            ]) 
            
            / 
            
            70.0
            
            ;
           
           
           
                   
            
            out
            
            [
            
            1
            
            ] 
            
            = 
            
            (
            
            2.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            27.0 
            
            * 
            
            in
            
            [
            
            1
            
            ] 
            
            + 
            
            12.0 
            
            * 
            
            in
            
            [
            
            2
            
            ] 
            
            - 
            
            8.0 
            
            * 
            
            in
            
            [
            
            3
            
            ] 
            
            + 
            
            2.0 
            
            * 
            
            in
            
            [
            
            4
            
            ]) 
            
            / 
            
            35.0
            
            ;
           
           
           
                   
            
            for 
            
            ( 
            
            i 
            
            = 
            
            2
            
            ; 
            
            i 
            
            <= 
            
            N 
            
            - 
            
            3
            
            ; 
            
            i
            
            ++ 
            
            )
           
           
           
                   
            
            {
             
           
           
           
                       
            
            out
            
            [
            
            i
            
            ] 
            
            = 
            
            (
            
            -
            
            3.0 
            
            * 
            
            (
            
            in
            
            [
            
            i 
            
            - 
            
            2
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            2
            
            ])
            
            + 
            
            12.0 
            
            * 
            
            (
            
            in
            
            [
            
            i 
            
            - 
            
            1
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            1
            
            ]) 
            
            + 
            
            17.0 
            
            * 
            
            in
            
            [
            
            i
            
            ] 
            
            ) 
            
            / 
            
            35.0
            
            ;
           
           
           
                   
            
            }
           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            = 
            
            (
            
            2.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            5
            
            ] 
            
            - 
            
            8.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            4
            
            ] 
            
            + 
            
            12.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            + 
            
            27.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            + 
            
            2.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ]) 
            
            / 
            
            35.0
            
            ;
           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            = 
            
            (
            
            - 
            
            in
            
            [
            
            N 
            
            - 
            
            5
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            4
            
            ] 
            
            - 
            
            6.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            + 
            
            69.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ]) 
            
            / 
            
            70.0
            
            ;
           
           
           
               
            
            }
           
           
           
               
            
            return
            
            ;
           
           
           
           
            
            }
           
           
           
           

           
           
           
           
            
            void 
            
            cubicSmooth7
            
            (
            
            double 
            
            in
            
            [], 
            
            double 
            
            out
            
            [], 
            
            int 
            
            N
            
            )
           
           
           
           
            
            {
             
           
           
           
               
            
            int 
            
            i
            
            ;
           
           
           
               
            
            if 
            
            ( 
            
            N 
            
            < 
            
            7 
            
            )
           
           
           
               
            
            {
             
           
           
           
                   
            
            for 
            
            ( 
            
            i 
            
            = 
            
            0
            
            ; 
            
            i 
            
            <= 
            
            N 
            
            - 
            
            1
            
            ; 
            
            i
            
            ++ 
            
            )
           
           
           
                   
            
            {
             
           
           
           
                       
            
            out
            
            [
            
            i
            
            ] 
            
            = 
            
            in
            
            [
            
            i
            
            ];
           
           
           
                   
            
            }
           
           
           
               
            
            }
           
           
           
               
            
            else
           
           
           
               
            
            {
             
           
           
           
                   
            
            out
            
            [
            
            0
            
            ] 
            
            = 
            
            ( 
            
            39.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            8.0 
            
            * 
            
            in
            
            [
            
            1
            
            ] 
            
            - 
            
            4.0 
            
            * 
            
            in
            
            [
            
            2
            
            ] 
            
            - 
            
            4.0 
            
            * 
            
            in
            
            [
            
            3
            
            ] 
            
            +
           
           
           
                             
            
            1.0 
            
            * 
            
            in
            
            [
            
            4
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            5
            
            ] 
            
            - 
            
            2.0 
            
            * 
            
            in
            
            [
            
            6
            
            ] 
            
            ) 
            
            / 
            
            42.0
            
            ;
           
           
           
                   
            
            out
            
            [
            
            1
            
            ] 
            
            = 
            
            ( 
            
            8.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            19.0 
            
            * 
            
            in
            
            [
            
            1
            
            ] 
            
            + 
            
            16.0 
            
            * 
            
            in
            
            [
            
            2
            
            ] 
            
            + 
            
            6.0 
            
            * 
            
            in
            
            [
            
            3
            
            ] 
            
            -
           
           
           
                             
            
            4.0 
            
            * 
            
            in
            
            [
            
            4
            
            ] 
            
            - 
            
            7.0
            
            * 
            
            in
            
            [
            
            5
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            6
            
            ] 
            
            ) 
            
            / 
            
            42.0
            
            ;
           
           
           
                   
            
            out
            
            [
            
            2
            
            ] 
            
            = 
            
            ( 
            
            -
            
            4.0 
            
            * 
            
            in
            
            [
            
            0
            
            ] 
            
            + 
            
            16.0 
            
            * 
            
            in 
            
            [
            
            1
            
            ] 
            
            + 
            
            19.0 
            
            * 
            
            in
            
            [
            
            2
            
            ] 
            
            + 
            
            12.0 
            
            * 
            
            in
            
            [
            
            3
            
            ] 
            
            +
           
           
           
                             
            
            2.0 
            
            * 
            
            in
            
            [
            
            4
            
            ] 
            
            - 
            
            4.0 
            
            * 
            
            in
            
            [
            
            5
            
            ] 
            
            + 
            
            1.0 
            
            * 
            
            in
            
            [
            
            6
            
            ] 
            
            ) 
            
            / 
            
            42.0
            
            ;
           
           
           
                   
            
            for 
            
            ( 
            
            i 
            
            = 
            
            3
            
            ; 
            
            i 
            
            <= 
            
            N 
            
            - 
            
            4
            
            ; 
            
            i
            
            ++ 
            
            )
           
           
           
                   
            
            {
             
           
           
           
                       
            
            out
            
            [
            
            i
            
            ] 
            
            = 
            
            ( 
            
            -
            
            2.0 
            
            * 
            
            (
            
            in
            
            [
            
            i 
            
            - 
            
            3
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            3
            
            ]) 
            
            +
           
           
           
                                  
            
            3.0 
            
            * 
            
            (
            
            in
            
            [
            
            i 
            
            - 
            
            2
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            2
            
            ]) 
            
            +
           
           
           
                                 
            
            6.0 
            
            * 
            
            (
            
            in
            
            [
            
            i 
            
            - 
            
            1
            
            ] 
            
            + 
            
            in
            
            [
            
            i 
            
            + 
            
            1
            
            ]) 
            
            + 
            
            7.0 
            
            * 
            
            in
            
            [
            
            i
            
            ] 
            
            ) 
            
            / 
            
            21.0
            
            ;
           
           
           
                   
            
            }
           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            = 
            
            ( 
            
            -
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            + 
            
            16.0 
            
            * 
            
            in 
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            + 
            
            19.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            +
           
           
           
                                 
            
            12.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            4
            
            ] 
            
            + 
            
            2.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            5
            
            ] 
            
            - 
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            6
            
            ] 
            
            + 
            
            1.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            7
            
            ] 
            
            ) 
            
            / 
            
            42.0
            
            ;
           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            = 
            
            ( 
            
            8.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            + 
            
            19.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            + 
            
            16.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            +
           
           
           
                                 
            
            6.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            4
            
            ] 
            
            - 
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            5
            
            ] 
            
            - 
            
            7.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            6
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            7
            
            ] 
            
            ) 
            
            / 
            
            42.0
            
            ;
           
           
           
                   
            
            out
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            = 
            
            ( 
            
            39.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            1
            
            ] 
            
            + 
            
            8.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            2
            
            ] 
            
            - 
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            3
            
            ] 
            
            -
           
           
           
                                 
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            4
            
            ] 
            
            + 
            
            1.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            5
            
            ] 
            
            + 
            
            4.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            6
            
            ] 
            
            - 
            
            2.0 
            
            * 
            
            in
            
            [
            
            N 
            
            - 
            
            7
            
            ] 
            
            ) 
            
            / 
            
            42.0
            
            ;
           
           
           
               
            
            }
           
           
           
           
            
            }
           
           
来自CODE的代码片 cubicSmooth.c

上面的代码经过了简单的测试,可以放心使用。

最近还有人向我要9点线性平滑和11点线性平滑的系数。我简单算了算,把系数列在了后面。不过我觉得这两组系数意义不大,与其这样做还不如设计一个FIR 滤波器或者 SG 滤波器。

9点线性平滑

yy[0]=(17*y[0] + 14*y[1] + 11*y[2] + 8*y[3] + 5*y[4] + 2*y[5] – y[6] – 4*y[7] – 7*y[8])/45;
yy[1]=(56*y[0] + 47*y[1] + 38*y[2] + 29*y[3] + 20*y[4] + 11*y[5] + 2*y[6] – 7*y[7] – 16*y[8])/180;
yy[2]=(22*y[0] + 19*y[1] + 16*y[2] + 13*y[3] + 10*y[4] + 7*y[5] + 4*y[6] + y[7] – 2*y[8])/90;
yy[3]=(32*y[0] + 29*y[1] + 26*y[2] + 23*y[3] + 20*y[4] + 17*y[5] + 14*y[6] + 11*y[7] + 8*y[8])/ 180;

yy[4]=(y[0] + y[1] +  y[2] + y[3] + y[4] + y[5] + y[6] + y[7] + y[8])/9;

yy[5]=(8*y[0] + 11*y[1] + 14*y[2] + 17*y[3] + 20*y[4] + 23*y[5] + 26*y[6] + 29*y[7] + 32*y[8])/ 180;
yy[6]=(-2*y[0] + y[1] + 4*y[2] + 7*y[3] + 10*y[4] + 13*y[5] + 16*y[6] + 19*y[7] + 22*y[8])/90;
yy[7]=(-16*y[0] – 7*y[1] +  2*y[2] + 11*y[3] + 20*y[4] + 29*y[5] + 38*y[6] + 47*y[7] + 56*y[8])/ 180;
yy[8]=(-7*y[0] – 4*y[1] – y[2] + 2*y[3] + 5*y[4] + 8*y[5] + 11*y[6] + 14*y[7] + 17*y[8])/45;

11点线性平滑

yy[0]=0.3181818181818182*

      y[0] + 0.2727272727272727*y[1] + 0.22727272727272727*y[2] +

    0.18181818181818182*y[3] + 0.13636363636363635*y[4] +

    0.09090909090909091*y[5] + 0.045454545454545456*y[6] +

    1.6152909428804953*^-17*y[7] – 0.045454545454545456*y[8] –

    0.09090909090909091*y[9] – 0.13636363636363635*y[10]

yy[1]=0.27272727272727276*

      y[0] + 0.23636363636363633*y[1] + 0.19999999999999998*y[2] +

    0.16363636363636364*y[3] + 0.12727272727272726*y[4] +

    0.09090909090909091*y[5] + 0.05454545454545455*y[6] +

    0.018181818181818202*y[7] – 0.01818181818181818*y[8] –

    0.054545454545454536*y[9] – 0.09090909090909088*y[10]

yy[2]=0.2272727272727273*

      y[0] + 0.19999999999999996*y[1] + 0.17272727272727267*y[2] +

    0.14545454545454542*y[3] + 0.11818181818181815*y[4] +

    0.09090909090909091*y[5] + 0.06363636363636363*y[6] +

    0.03636363636363638*y[7] + 0.009090909090909094*y[8] –

    0.01818181818181816*y[9] – 0.0454545454545454*y[10]

yy[3]=0.18181818181818188*

      y[0] + 0.16363636363636355*y[1] + 0.1454545454545454*y[2] +

    0.12727272727272723*y[3] + 0.10909090909090904*y[4] +

    0.0909090909090909*y[5] + 0.07272727272727272*y[6] +

    0.054545454545454564*y[7] + 0.036363636363636376*y[8] +

    0.01818181818181823*y[9] + 8.326672684688674*^-17*y[10]

yy[4]=0.13636363636363644*

      y[0] + 0.12727272727272718*y[1] + 0.11818181818181811*y[2] +

    0.10909090909090903*y[3] + 0.09999999999999995*y[4] +

    0.0909090909090909*y[5] + 0.08181818181818182*y[6] +

    0.07272727272727275*y[7] + 0.06363636363636364*y[8] +

    0.05454545454545459*y[9] + 0.04545454545454555*y[10]

yy[5]=0.090909090909091*

      y[0] + 0.09090909090909077*y[1] + 0.09090909090909083*y[2] +

    0.09090909090909083*y[3] + 0.09090909090909084*y[4] +

    0.0909090909090909*y[5] + 0.09090909090909091*y[6] +

    0.09090909090909094*y[7] + 0.09090909090909093*y[8] +

    0.090909090909091*y[9] + 0.09090909090909102*y[10]

yy[6]=0.04545454545454558*

      y[0] + 0.0545454545454544*y[1] + 0.06363636363636352*y[2] +

    0.07272727272727264*y[3] + 0.08181818181818173*y[4] +

    0.0909090909090909*y[5] + 0.1*y[6] + 0.10909090909090911*y[7] +

    0.11818181818181821*y[8] + 0.12727272727272737*y[9] +

    0.13636363636363652*y[10]

yy[7]=1.1102230246251565*^-\

16*y[0] + 0.01818181818181802*y[1] + 0.03636363636363624*y[2] +

    0.05454545454545445*y[3] + 0.07272727272727264*y[4] +

    0.0909090909090909*y[5] + 0.10909090909090909*y[6] +

    0.12727272727272732*y[7] + 0.1454545454545455*y[8] +

    0.16363636363636372*y[9] + 0.181818181818182*y[10]

yy[8]=-0.0454545454545453*

      y[0] – 0.018181818181818354*y[1] + 0.009090909090908955*y[2] +

    0.03636363636363624*y[3] + 0.06363636363636355*y[4] +

    0.09090909090909088*y[5] + 0.11818181818181818*y[6] +

    0.1454545454545455*y[7] + 0.17272727272727273*y[8] +

    0.2000000000000001*y[9] + 0.22727272727272746*y[10]

yy[9]=-0.09090909090909072*

      y[0] – 0.05454545454545473*y[1] – 0.018181818181818327*y[2] +

    0.01818181818181805*y[3] + 0.05454545454545444*y[4] +

    0.09090909090909088*y[5] + 0.12727272727272726*y[6] +

    0.16363636363636366*y[7] + 0.2*y[8] + 0.23636363636363647*y[9] +

    0.27272727272727293*y[10]

yy[10]=-0.1363636363636362*

      y[0] – 0.09090909090909116*y[1] – 0.04545454545454561*y[2] –

    1.6653345369377348*^-16*y[3] + 0.04545454545454533*y[4] +

    0.09090909090909088*y[5] + 0.13636363636363635*y[6] +

    0.18181818181818188*y[7] + 0.2272727272727273*y[8] +

    0.27272727272727293*y[9] + 0.3181818181818184*y[10]

    原文作者:yixixi
    原文地址: https://blog.csdn.net/yixixi/article/details/50478182
    本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
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