又一道动态规划算法题

Ignatius and the Princess III

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)


Problem Description


“Well, it seems the first problem is too easy. I will let you know how foolish you are later.” feng5166 says.

“The second problem is, given an positive integer N, we define an equation like this:
  N=a[1]+a[2]+a[3]+…+a[m];
  a[i]>0,1<=m<=N;
My question is how many different equations you can find for a given N.
For example, assume N is 4, we can find:
  4 = 4;
  4 = 3 + 1;
  4 = 2 + 2;
  4 = 2 + 1 + 1;
  4 = 1 + 1 + 1 + 1;
so the result is 5 when N is 4. Note that “4 = 3 + 1” and “4 = 1 + 3″ is the same in this problem. Now, you do it!”


 


Input


The input contains several test cases. Each test case contains a positive integer N(1<=N<=120) which is mentioned above. The input is terminated by the end of file.


 


Output


For each test case, you have to output a line contains an integer P which indicates the different equations you have found.


 


Sample Input

4

10

20

 


Sample Output

5

42

627

 

问题是这样的,给定一个正整数N(小于等于120),如N=3,则N可以表示为1+1+11+23,这三种正整数相加的形式。注意,1+22+1被视为是一种。要求输出N共有几组这样的表达式。又比如,4可以表示为1+1+1+11+1+21+32+24,这五种表达式,所以输入是4,输出是5

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