c# – “同步”异步方法的开销是多少？

2023年4月12日 151次阅读

这是方法返回任务的基准,但在引擎盖下同步运行.

class MainClass
{
    public static async Task<int> UsingAsyncModifier()
    {
        return 10;
    }

    public static Task<int> UsingTaskCompletionSource()
    {
        TaskCompletionSource<int> tcs = new TaskCompletionSource<int>();
        tcs.SetResult(10);
        return tcs.Task;
    }

    public static Task<int> UsingTaskFromResult()
    {
        return Task.FromResult(10);
    }

    public static void Main(string[] args)
    {
        DateTime t = DateTime.Now;
        const int repeat = 10000; // Results volatile while repeat grows.
        Console.WriteLine("Repeat {0} times.", repeat);

        int j = 0;
        for (int i = 0; i < repeat; i++)
        {
            j += UsingAsyncModifier().Result;
        }
        Console.WriteLine("UsingAsyncModifier: {0}", DateTime.Now - t);
        t = DateTime.Now;

        for (int i = 0; i < repeat; i++)
        {
            j += UsingTaskCompletionSource().Result;
        }
        Console.WriteLine("UsingTaskCompletionSource: {0}", DateTime.Now - t);
        t = DateTime.Now;

        for (int i = 0; i < repeat; i++)
        {
            j += UsingTaskFromResult().Result;
        }
        Console.WriteLine("UsingTaskFromResult: {0}", DateTime.Now - t);
    }
}

输出(重复10,000 / 100,000 / 1000,000次)：

Repeat 10000 times.
UsingAsyncModifier: 00:00:00.1043980
UsingTaskCompletionSource: 00:00:00.0095270
UsingTaskFromResult: 00:00:00.0089460

重复10,000次,UsingTaskFromResult比UsingAsyncModifier快10倍.

Repeat 100000 times.
UsingAsyncModifier: 00:00:00.1676000
UsingTaskCompletionSource: 00:00:00.0872020
UsingTaskFromResult: 00:00:00.0870180

重复100,000次,UsingTaskFromResult比UsingAsyncModifier快2倍.

Repeat 1000000 times.
UsingAsyncModifier: 00:00:00.8458490
UsingTaskCompletionSource: 00:00:00.8870980
UsingTaskFromResult: 00:00:00.9027320

重复1,000,000次,UsingAsyncModifier比UsingTaskFromResult稍快.

我认为,async修饰符只是创建了一个完成的Task,类似于Task.FromResult().但基准并不能证明我的想法.
为什么？

最佳答案 虽然我使用DateTime看到了类似的结果,但使用秒表进行时间测量表明,使用UsingAsyncModifier()的迭代时间比使用UsingTaskCompletionSource()或UsingTaskFromResult()要长2倍,两者都显示相等的持续时间,即使是1 000 000次迭代

这是输出：

Repeat 1000000 times.
UsingAsyncModifier: 5458
UsingTaskCompletionSource: 2838
UsingTaskFromResult: 2556

用你的代码使用秒表

class Program
{
     public static async Task<int> UsingAsyncModifier()
    {
        return 10;
    }

    public static Task<int> UsingTaskCompletionSource()
    {
        TaskCompletionSource<int> tcs = new TaskCompletionSource<int>();
        tcs.SetResult(10);
        return tcs.Task;
    }
    public static Task<int> UsingTaskFromResult()
    {
        return TaskEx.FromResult(10);
    }
    static void Main(string[] args)
    {
      //DateTime t = DateTime.Now;
      Stopwatch timer = new Stopwatch();
      const int repeat = 1000*1000; // Results volatile while repeat grows.
      Console.WriteLine("Repeat {0} times.", repeat);

        int j = 0;
        //DateTime t = DateTime.Now;
        timer.Start();
        for (int i = 0; i < repeat; i++)
        {
            j += UsingAsyncModifier().Result;
        }
        timer.Stop();
        Console.WriteLine("UsingAsyncModifier: {0}"
                          , timer.ElapsedMilliseconds);
        //t = DateTime.Now;
        timer.Reset();

        j = 0;

        timer.Start();
        for (int i = 0; i < repeat; i++)
        {
            j += UsingTaskCompletionSource().Result;
        }
        timer.Stop();
        Console.WriteLine("UsingTaskCompletionSource: {0}"
                           , timer.ElapsedMilliseconds);
        //t = DateTime.Now;
        timer.Reset();
        j = 0;
        timer.Start();
        for (int i = 0; i < repeat; i++)
        {
          j += UsingTaskFromResult().Result;
        }
        timer.Stop();
        Console.WriteLine("UsingTaskFromResult: {0}"
                          , timer.ElapsedMilliseconds);

        Console.ReadLine();
    }
}

Stephen Toub在他的“Async Performance: Understanding the Costs of Async and Await”中解释道：

When working with synchronous code, methods with empty bodies are
practically free. This is not the case for asynchronous methods

阅读它以获取更多详细信息

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