javascript – 无法使用.not()或：不正确

2023年8月12日 218次阅读

为什么我无法将.red类添加到.out但排除最接近的？

$('.ring').on('click', function() {

  $(this).not().closest('out').addClass('red');
});
div {
  height: 100px;
  width: 100px;
  float: left;
  margin: 2px;
}

.ring {
  background: grey;
}

.out {
  background: khaki;
}

.red {
  background: red;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="map">
  <div class="data">
    <div class="ring"></div>
  </div>
  <div class="out"></div>
</div>
<div class="map">
  <div class="data">
    <div class="ring"></div>
  </div>
  <div class="out"></div>
</div>
<div class="map">
  <div class="data">
    <div class="ring"></div>
  </div>
  <div class="out"></div>
</div>
<div class="map">
  <div class="data">
    <div class="ring"></div>
  </div>
  <div class="out"></div>
</div>
<div class="map">
  <div class="data">
    <div class="ring"></div>
  </div>
  <div class="out"></div>
</div>

最佳答案 我会使用这样的索引来做到这一点：

$('.ring').on('click', function() {
  $(".red").removeClass("red");
  var index = $(".ring").index(this);  
  $(".out").not(":eq("+index+")").addClass('red');
});
div {
  height: 100px;
  width: 100px;
  float: left;
  margin: 2px;
}

.ring {
  background: grey;
}

.out {
  background: khaki;
}

.red {
  background: red;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="map">
  <div class="data">
    <div class="ring"></div>
  </div>
  <div class="out"></div>
</div>
<div class="map">
  <div class="data">
    <div class="ring"></div>
  </div>
  <div class="out"></div>
</div>
<div class="map">
  <div class="data">
    <div class="ring"></div>
  </div>
  <div class="out"></div>
</div>
<div class="map">
  <div class="data">
    <div class="ring"></div>
  </div>
  <div class="out"></div>
</div>
<div class="map">
  <div class="data">
    <div class="ring"></div>
  </div>
  <div class="out"></div>
</div>
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