php – Laravel Queue – 记住属性状态？

2023年9月16日 176次阅读

如果作业失败,它将被推回到队列.有没有办法在再次处理作业时记住作业类中的属性值？

例如：

class MailJob extends Job
{
    public $tries = 3;

    public $status;


    public function __construct()
    {
        $this->status = false; // set to false
    }


    /**
     * Execute the job.
     */
    public function handle()
    {
        $this->status = true;
        // Assume job has failed, it went back to the Queue.
        // status should be true when this job start processing again
    }
}

最佳答案 如果要在同一时刻再次重新运行失败的进程.你可以做这样的事情.

在重新运行作业时,对象在内存中,因此数据可用.

我没有通过运行验证它,但希望它能工作

class MailJob extends Job{
public $tries = 3;
public $status;


public function __construct()
{
    $this->status = false; // set to false
}


/**
 * Execute the job.
 */
public function handle()
{
    $this->status = true;
    // Assume job has failed, it went back to the Queue.
    // status should be true when this job start processing again

    $failed = processFailedisConfirm();

    if $failed == true && $this->tries > -1 {
         $this->tries = $this->tries - 1;
         $this->handel();
    }
}}

processFailedisConfirm的示例可以是

public function processFailedisConfirm(){

     // Core Process to be done in the Job
     $state = (Do Some Api Call); // Here just example, you may send email
                                  // Or can do the core Job Process
                                  // And depending on the Response of the 
                                  // Process return true or false

     // Is Job failed or not ?
     if ( $state == "200" ){
     return false; // Job is not failed
     } else {
     return true; // Job is failed
}

过程逻辑失败与否取决于您正在进行的操作.因为我正在进行api调用,如果我得到200的响应,我的过程是成功的.
否则进程失败.
这个例子,不同api的成功响应可能与api设计师的desigend不同.

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