python – 查找10,000位数字中13个相邻数字的最大乘积

2023年9月15日 338次阅读

似乎无法弄清楚我的代码有什么问题(Project Euler问题8).我想在下面的10,000位数字中找到13个相邻数字的最大乘积,我的答案是错误的.

my_list = list('7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450')

for i in range(1000):
    my_list[i] = int(my_list[i])

previous_product = 1
for x in range(13):
  previous_product *= my_list[x]
current_product = previous_product*my_list[13]/my_list[0]

for i in range(1, 987):
  if current_product > previous_product:
    maximum_product = current_product
  previous_product = current_product
  if my_list[i]==0:
    current_product = 1
    for x in range(13):
      current_product *= my_list[i+x+1]
  else:
    current_product = previous_product*my_list[i+x+1]/my_list[i]

print(maximum_product)

编辑：解决了！ maximum_product的定义错误…它采用了最新“当前产品”的价值,该价值恰好大于以前的产品,不一定是最大的产品.

正确,尽管不是超级高效的代码：

   my_list = list('7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450')

for i in range(1000):
    my_list[i] = int(my_list[i])

previous_product = 1
for x in range(13):
  previous_product *= my_list[x]
current_product = previous_product*my_list[13]/my_list[0]

large_products = []

for i in range(1, 987):
  if current_product > previous_product:
    large_products.append(current_product)
  previous_product = current_product
  if my_list[i]==0:
    current_product = 1
    for x in range(13):
      current_product *= my_list[i+x+1]
  else:
    current_product = previous_product*my_list[i+x+1]/my_list[i]

print(max(large_products))

最佳答案 我没有检查为什么你的方法不起作用,但你可以轻松解决这个问题：

import operator
from functools import reduce

my_int_list = [int(char) for char in my_list]

max(map(lambda *x: reduce(operator.mul, x), 
        my_int_list[0:], 
        my_int_list[1:], 
        my_int_list[2:], 
        my_int_list[3:], 
        my_int_list[4:], 
        my_int_list[5:], 
        my_int_list[6:], 
        my_int_list[7:], 
        my_int_list[8:], 
        my_int_list[9:], 
        my_int_list[10:], 
        my_int_list[11:], 
        my_int_list[12:]))

如果这占用了太多内存,您也可以使用itertools.islice而不是使用[idx：]直接切片.

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