ios – 在Swift 2中使用Alamofire进行错误处理

2023年9月14日 132次阅读

嗨,我正在练习一些代码,我的代码很好用case .Success(let value)：它显示警告但会出现故障.故障(让错误)：用4xx类状态代码显示警告？

  Alamofire.request(.GET, URL).responseJSON { (response) -> Void in
            if let value = response.result.value {

             let json = JSON(value)

             switch response.result {
             case .Success(let value):

             let name = json["name"].string
             if let nothing = name {
             self.alertMessage(message: "Name not Found")
                    } else {
            self.alertMessage(message: "Name Found")
                    }
            case .Failure(let error):
            self.alertMessage(message: "Error 4xx / 5xx")
                }

最佳答案 您可以使用验证来检查状态代码：

Alamofire.request(.GET, URL)
    .validate()    // or, if you just want to check status codes, validate(statusCode: 200..<300)
    .responseJSON { response in
        switch response.result {
        case .Success(let value):
            let json = JSON(value)

            if let name = json["name"].string {
                self.alertMessage(message: "Name Found: \(name)")
            } else {
                self.alertMessage(message: "Name not Found")
            }
        case .Failure(let error):
            self.alertMessage(message: "Error 4xx / 5xx: \(error)")
        }
}

或者,在Swift 3中：

Alamofire.request(url)
    .validate()    // or, if you just want to check status codes, validate(statusCode: 200..<300)
    .responseJSON { response in
        switch response.result {
        case .success(let value):
            let json = JSON(value)

            if let name = json["name"].string {
                self.alertMessage(message: "Name Found: \(name)")
            } else {
                self.alertMessage(message: "Name not Found")
            }
        case .failure(let error):
            self.alertMessage(message: "Error 4xx / 5xx: \(error)")
        }
}

另请注意,您应该将response.result.value的检查移到Success部分内部(或者只是获取传递的值).此外,确定是否找到名称是向后的.

点赞