我有一个ReportBuilder类用于生成文档(Excel).我想要的是选择员工和日期,然后计算该日期的总工作时间.这是我的php文件
<?php
class EmployeeSummaryTimesheet extends ReportBuilder{
public function getMainQuery(){
$query = "SELECT
(SELECT `employee_id` from Employees where id = at.employee) as 'Employee',
(SELECT concat(`first_name`,' ',`middle_name`,' ', `last_name`) from Employees where id = at.employee) as 'Employee',
TIMEDIFF(out_time, in_time) as 'Working Hours'
FROM Attendance at";
return $query;
}
public function getWhereQuery($request){
if(($request['employee'] != "NULL" && !empty($request['employee']))){
$query = "where employee = ? and in_time >= ? and out_time <= ? group by employee;";
$params = array(
$request['employee'],
$request['date_start']." 00:00:00",
$request['date_end']." 23:59:59",
);
}else{
$query = "where in_time >= ? and out_time <= ? group by employee;";
$params = array(
$request['date_start']." 00:00:00",
$request['date_end']." 23:59:59",
);
}
return array($query, $params);
}}
现在我无法得到那个特定日期的总和我第一天获得TIMEDIFF(out_time,in_time)值只是没有工作时间总和帮助我
编辑 – 这里我有两个表Employee和Attendance(id,employee(这是Employee表中的员工ID),in_time,out_time)
编辑:我将DATE_FORMAT(in_time,’%Y-%m-%d’)取消为’Date’,我不需要此列
最佳答案 您希望每位员工和日期有一条记录,并显示该员工当天的总工作时间.因此,按员工和日期加入和分组,并将工作时间相加.
select
e.employee_id,
concat(e.first_name, ' ', e.middle_name, ' ', e.last_name) as employee_name
date_format(at.in_time, '%Y-%m-%d') as 'Date',
sum(timediff(at.out_time, at.in_time)) as 'Working Hours'
from attendance at
join employee e on e.id = at.employee
where ...
group by e.employee_id, date_format(at.in_time, '%Y-%m-%d');