机器学习算法【11】--推荐系统实战

2023年11月20日 205次阅读 来源: 不曾走远~

前言：本文是机器学习实战中的案例，餐馆菜肴推荐系统

from numpy import *
from numpy import linalg as la

# 载入数据 (用户-菜肴矩阵)
# 行为 用户, 列为希肴, 表示用户对某个菜肴的评分
def loadExData2():
    return[[0, 0, 0, 0, 0, 4, 0, 0, 0, 0, 5],
           [0, 0, 0, 3, 0, 4, 0, 0, 0, 0, 3],
           [0, 0, 0, 0, 4, 0, 0, 1, 0, 4, 0],
           [3, 3, 4, 0, 0, 0, 0, 2, 2, 0, 0],
           [5, 4, 5, 0, 0, 0, 0, 5, 5, 0, 0],
           [0, 0, 0, 0, 5, 0, 1, 0, 0, 5, 0],
           [4, 3, 4, 0, 0, 0, 0, 5, 5, 0, 1],
           [0, 0, 0, 4, 0, 4, 0, 0, 0, 0, 4],
           [0, 0, 0, 2, 0, 2, 5, 0, 0, 1, 2],
           [0, 0, 0, 0, 5, 0, 0, 0, 0, 4, 0],
           [1, 0, 0, 0, 0, 0, 0, 1, 2, 0, 0]]

# 计算两个评分的欧氏距离
def esclidSim(inA,inB):
    if len(inA)<3:
        return 1.0
    return 1.0/(1.0+la.norm(inA-inB))
# 计算两个评分的 皮尔逊相关系数 (Pearson Correlation)
def pearsSim(inA,inB):
    if len(inA)<3:
        return 1.0
    return 0.5+0.5*corrcoef(inA.inB)[0][1]
# 计算两个评分的余弦相似度 (Cosine similarity)
def cosSim(inA,inB):
    num = float(inA.T*inB)
    denom = la.norm(inA)*la.norm(inB)
    return 0.5+0.5*(num/denom)

# 基于物品的相似度推荐
def standEst(dataMat,user,sinMeas,item):
    n = shape(dataMat)[1]
    simTotal = 0.0;ratsimTotal = 0.0
    for j in range(n):
        userRating = dataMat[user,j]
        if userRating ==0:
            continue
        overLap = nonzero(logical_and(dataMat[:,item].A>0,dataMat[:,j].A>0))[0]
        if len(overLap)==0:
            simility =0
        else:
            simility = sinMeas(dataMat[overLap,item],dataMat[overLap,j])
            print("the %d and %d similit is :%f"%(item,j,simility))
        simTotal +=simility
        ratsimTotal+=simility*userRating
    if simTotal == 0:
        return 0
    else:
        return ratsimTotal/simTotal

def recommand(dataMat,user,n=3,simMeans=cosSim,estMethod =standEst):
    unratedItems = nonzero(dataMat[user,:].A==0)[1]
    if len(unratedItems)==0:
        return "you rated everything"
    itemScores =[]
    for item in unratedItems:
        estimatscore = estMethod(dataMat,user,simMeans,item)
        itemScores.append((item,estimatscore))
    return sorted(itemScores,key = lambda jj:jj[1],reverse=True)[:n]

myMat = mat(loadExData2())
print(recommand(myMat, 1))


运行结果：
the 0 and 10 similit is :1.000000
the 1 and 10 similit is :1.000000
the 2 and 10 similit is :1.000000
the 6 and 3 similit is :1.000000
the 6 and 5 similit is :1.000000
the 6 and 10 similit is :1.000000
the 7 and 10 similit is :1.000000
the 8 and 10 similit is :1.000000
the 9 and 3 similit is :1.000000
the 9 and 5 similit is :1.000000
the 9 and 10 similit is :1.000000
[(6, 3.3333333333333335), (9, 3.3333333333333335), (0, 3.0)]

Process finished with exit code 0

 

    原文作者：不曾走远~
    原文地址: https://blog.csdn.net/qq_20412595/article/details/82556692
    本文转自网络文章，转载此文章仅为分享知识，如有侵权，请联系博主进行删除。
点赞