#include<stdlib.h> #include<string.h> #include<iostream> using namespace std; #define FALSE 1 typedef struct StackNode{ char op; StackNode * next; }StackNode,*StackTop; char operation[50];int length; //链式栈栈顶 StackTop top=(StackNode *)malloc(sizeof(StackNode)); //初始化链式栈 void InitialStack() { top->next=NULL; } //判断栈是否为空 bool IsEmpty() { bool flag_bool; top->next==NULL?flag_bool=true:flag_bool=false; return flag_bool; } //将栈顶元素Pop,并返回栈顶元素值 char Pop() { StackNode * temp=(StackNode *)malloc(sizeof(StackNode)); temp=top->next; if(temp==NULL)return FALSE; char op=temp->op; top->next=temp->next; free(temp); return op; } //取栈顶元素值 char GetTop() { return top->next==NULL?FALSE:top->next->op; } //将新元素压入栈 void Push(char char_op) { StackNode * temp=(StackNode *)malloc(sizeof(StackNode)); temp->op=char_op; temp->next=top->next; top->next=temp; } //判断括号与栈顶的左括号是否匹配 bool Match(char op1,char op2) { if((op1=='('&&op2==')')||(op1=='{'&&op2=='}')||(op1=='['&&op2==']')) return true; else return false; } void procExecute() { length=strlen(operation); for(int i=0;i<length;i++) { switch(operation[i]){ case '(': case '{': case '[': Push(operation[i]); break; case ')': case '}': case ']': if(IsEmpty()){ cout<<"右括号多余\n"; return; }else{ if(Match(GetTop(),operation[i])){ Pop();break; } else{ cout<<"左右括号不匹配\n"; return; } } } } if(IsEmpty()) cout<<"括号匹配成功!\n"; else cout<<"左括号多余\n"; } int main() { while(cin>>operation) { InitialStack(); procExecute(); } return 0; }
链式栈实现括号匹配问题
原文作者:括号匹配问题
原文地址: https://blog.csdn.net/iteye_16572/article/details/81888669
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原文地址: https://blog.csdn.net/iteye_16572/article/details/81888669
本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。