C语言随机发牌

#include "stdafx.h"
#include<time.h>
#include<stdlib.h>

int card[54];//保存每张牌的数字符号
bool flag[54];//标记数组 false 代表这个单元编号的牌没抽过
void show1();
void mix1();
int main()
{
    srand(time(NULL));
    mix1();
    show1();
    int a;
    scanf_s("%d", &a);
    return 0;
}
void mix1() {
    int c = 0;
    for (int i = 0; i < 54; i++) {
        c++;
        int a = rand() % 54;
        if (flag[a] == false) {
            card[i] = a;
            flag[a] = true;
        }
        else
        {
            i--;
        }
    }
    printf("c=%d\n", c);
}
void show1() {
    char flowers[4][10] = { "\3","\4","\5","\6" };
    char number[13][3] = { "A","2","3","4","5","6","7","8","9","10","J","Q","K" };
    for (int i = 0; i < 54; i++) {
        if (card[i] == 52) {
            printf("大王 ");
        }
        else if (card[i] == 53) {
            printf("小王 ");
        }
        else {
            printf("%s %s ", flowers[card[i] / 13], number[card[i] % 13]);
        }
        if ((i + 1) % 17 == 0)
        {
            printf("\n");
        }
    }
}
    原文作者:魔术师发牌问题
    原文地址: https://blog.csdn.net/sjz_yuwenpu/article/details/72188704
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