约瑟夫环问题:用户输入M,N值,从1至N开始顺序循环数数,每数到M输出该数值,直至全部输出。(采用循环链表)

#if 1
// 用户输入M,N值,从1至N开始顺序
// 循环数数,每数到M输出该数值,
// 直至全部输出
#include <stdio.h>
#include <stdlib.h>
#include <iostream>

using namespace std;

// 节点
typedef struct node
{
	int data;
	node* next;
}node;

// 创建循环链表
void createList(node*& head, node*& tail, int n)
{
	if (n<1)
	{
		head = NULL;
		return;
	}
	head = new node();
	head->data = 1;
	head->next = NULL;

	node* p = head;
	for (int i = 2; i<n + 1; i++)
	{
		p->next = new node();
		p = p->next;
		p->data = i;
		p->next = NULL;
	}

	tail = p;
	p->next = head;
}

// 打印循环链表
void Print(node*& head)
{
	node* p = head;

	while (p && p->next != head)
	{
		printf("%d ", p->data);
		p = p->next;
	}
	if (p)
	{
		printf("%d\n", p->data);
	}
}

// 用户输入M,N值,从1至N开始顺序
// 循环数数,每数到M输出该数值,
// 直至全部输出
void CountPrint(node*& head, node*& tail, int m)
{
	node* cur = head;
	node* pre = tail;

	int cnt = m - 1;
	while (cur && cur != cur->next)
	{
		if (cnt)
		{
			cnt--;
			pre = cur;
			cur = cur->next;
		}
		else
		{
			pre->next = cur->next;
			printf("%d ", cur->data);
			delete cur;
			cur = pre->next;
			cnt = m - 1;
		}
	}

	if (cur)
	{
		printf("%d ", cur->data);
		delete cur;
		head = tail = NULL;
	}
	printf("\n");
}

int main()
{
	node* head = 0;
	node* tail = 0;
	int m;
	int n;
	cin >> n  >>m;
	
	createList(head, tail, n);
	Print(head);
	CountPrint(head, tail, m);
	system("pause");
	return 0;
}

#endif

 

    原文作者:约瑟夫环问题
    原文地址: https://blog.csdn.net/buknow/article/details/81941514
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