python暴力破解六位密码(数字和大小写字母)

1.破解六位数字的密码

废话不多说,给我上代码!

key = input('请输入六位数密码:')  #填写密码用来破解

while len(key)!=6:   #判断密码是否为六位,否则重新输入
    print('密码不合法,请重新输入!')
    key = input('请输入六位的密码:')
    print(key)
key = list(key)
print('设置的密码为:',key)
my_str = []
result = ['0','0','0','0','0','0']

#数字0-9的ASCII码为48-57
for j in range(48,58):
    my_str.append(chr(j))

for i in my_str:
    result[0] = i
    for j in my_str:
        result[1] = j
        for k in my_str:
            result[2] = k
            for l in my_str:
                result[3] = l
                for m in my_str:
                    result[4] = m
                    for n in my_str:
                        result[5] = n
                        if result == key:
                            print('破解成功!密码为:',result)
                            break
                        else:
                            print('失败',result)
                    else:
                        continue
                    break
                else:
                    continue
                break
            else:
                 continue
            break
        else:
            continue
        break
    else:
        continue
    break

2.破解六位数字大小写字母混合密码

key = input('请输入六位数密码:')  #填写密码用来破解
while len(key)!=6:
    print('密码不合法,请重新输入!')
    key = input('请输入六位的密码:')
key = list(key)
print('设置的密码为:',key)
my_str = []
result = ['0','0','0','0','0','0']

#产生数组进行比对                                       a = random.choice(my_str)
for j in range(48,123):
    if j  in [58,59,60,61,62,63,64,91,92,93,94,95,96]:
        continue
    my_str.append(chr(j))
# print(my_str)

for i in my_str:
    result[0] = i
    for j in my_str:
        result[1] = j
        for k in my_str:
            result[2] = k
            for l in my_str:
                result[3] = l
                for m in my_str:
                    result[4] = m
                    for n in my_str:
                        result[5] = n
                        if result == key:
                            print('破解成功!密码为:',result)
                            break
                        else:
                            print('失败',result)
                    else:
                        continue
                    break
                else:
                    continue
                break
            else:
                 continue
            break
        else:
            continue
        break
    else:
        continue
    break
提示:本方法为穷举法破解六位密码,但基于方法本身的缺陷,如果密码开头过大,会导致运行起来过慢,需要很长时间来破解,如876sG5这样以8这样比较大的数字开头就比较费时间。但是,本方法的优是不论耗费多长时间,总会、一定会破解成功。

学习笔记:

1.使用以下方法实现了break跳出嵌套的for循环(多层for循环)
for i in range(1,5):
    for j in range(5,10):
       	 print(i,j)
      	 if j==6:
          	 break
    else:
         continue
    break
2.数字和字母对应的ASCII码为
a-z     97-122
A-Z     65-90
0-9     48-57

数字、字母转ASCII码函数:ord()
ASCII码转数字、字母函数:chr()
3.从列表中产生随机数
my_str = ['h','e','l','i','o']
a = random.choice(my_str)
print(a)
    原文作者:H驱逐舰H
    原文地址: https://blog.csdn.net/weixin_45104240/article/details/104622177
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