Description

Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal digits.
Input

The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.
Output

For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.
Sample Input

2
6
19
0
Sample Output

10
100100100100100100
111111111111111111

把所有只含1和0的数枚举出来取余就行，然后用G++交才能过。。。

#include <iostream>
#include <cstring>
#include <string>
#include <vector>
#include <queue>
#include <map>
#include <algorithm>
#define INF 0x3f3f3f3f
#define MAXN 1010
using namespace std;
void bfs(int n)
{
    queue<long long> q;
    q.push(1);
    while(!q.empty())
    {
        long long tmp=q.front();
        q.pop();
        if(tmp%n==0)
        {
            cout<<tmp<<endl;
            break;
        }
        q.push(tmp*10);
        q.push(tmp*10+1);
    }
}
int main()
{
    ios::sync_with_stdio(false);
    int n;
    while(cin>>n&&n)
    {
        bfs(n);
    }
    return 0;
}