二叉树的几种创建方法

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@Author: 张海拔

@Update: 2014-01-28

@Link: http://www.cnblogs.com/zhanghaiba/p/3535769.html

 

二叉树这种数据结构非常经典。研究二叉树之前必须得创建二叉树,这里简单介绍三种常见的创建二叉树的方式——

             89
         ____|____
         |       |
         73      82
        _|__  ___|___
        |  |  |     |
              92    5
             _|__  _|__
             |  |  |  |
             69
            _|__
            |  |

(1)随机创建一棵二叉树

比如我们要随机生成含n个节点的二叉树,默认指定节点值的范围是[0, 100)

那么生成一个节点后,设随机生成的左子树包括节点数是left_n = random[0, n-1],则right_n = (n-1) – left_n

这样递归下去,当n<=0返回空,n==1返回一个根节点

该算法生成的二叉树是比较“平衡”的(期望情况下左子树和右子树数目差不多),原因是生成深度很浅时比深度很深时范围大,相对不容易取到边界值。

如上所示的二叉树,创建过程中,打印left_n和right_n结果会是:

left_n=1 right_n = 4

left_n=2 right_n = 1

left_n=1 right_n = 0

(2)根据二叉树的前序、中序或后序序列(同时包含空节点的序列)来创建

如上所示的二叉树,包括空节点的前序序列表示为:89 73 # # 82 92 69 # # # 5 # #(空节点标记为#)

中序、后序同理

(3)根据二叉树对应的“完全二叉树”序列来创建(设下标从0开始)

想象如上所示的二叉树嵌入到完全二叉树中,则从下标0~15,完全二叉树对应的序列是:

89 73 82 # # 92 5 # # # # 69 # # #

把序列存入数组order[]中,若设树的根节点值为order[idx],则其左子树根节点的值为order[idx*2 +1],右子树的为order[idx*2 +2]

(4)由遍历序列创建二叉树 link(public),这个已经单独介绍过了,包括给定中序前序创建和给定中序后序创建两种情况。

不过这种创建方式创建出来的二叉树有局限性:要求每个节点的“值”是不同的。

假如有两个节点“值”相同,比如完全二叉树的{1,1}和{1, #, 1},可以创建两棵不同的树,但它们的前序中序序列是完全一样的。

 

  1 /*
  2  *Author: ZhangHaiba
  3  *Date: 2014-1-28
  4  *File: binary_tree.c
  5  *
  6  *a demo shows three ways to create binary tree
  7  */
  8 #include <stdio.h>
  9 #include <stdlib.h>
 10 #include <time.h>
 11 #define MOD 100
 12 #define LEN 1024
 13 #define CMD_LEN 128
 14 
 15 typedef struct node* link;
 16 typedef struct node {
 17     int item;
 18     link left;
 19     link right;
 20 }node;
 21 
 22 //public
 23 link NODE(int item, link left, link right);
 24 link bt_create_by_random(int n);
 25 link bt_create_by_preorder(void);
 26 //idx begin with 0
 27 link bt_create_by_complete_bt_order(int *order, int order_len, int idx);
 28 link bt_preorder(link root);
 29 void bt_show_by_tree(link root);
 30 
 31 //private
 32 link bt_create_by_random_core(int n);
 33 void tree_print(link root, FILE *fd);
 34 
 35 
 36 int main(void)
 37 {
 38     char cmd[CMD_LEN];
 39     int n, i, order[LEN];
 40 
 41     printf("there is three ways to create binary tree, including:\n");
 42     printf("[r] create binary tree by random\n");
 43     printf("[p] create binary tree by preorder(NULL node values -1)\n");
 44     printf("[c] create binary tree by complete binary tree order(NULL node values -1)\n");
 45     printf("[q] quit\n");
 46     printf("please choice: enter charactor 'r' 'p' or 'c', or 'q' to quit\n");
 47     while(1) {
 48         scanf("%s", cmd);
 49         switch(cmd[0]) {
 50             case 'r':
 51             printf("create binary tree with n nodes by randmon, please assgin n:\n");
 52             scanf("%d", &n);
 53             link bt_tree_a = bt_create_by_random(n);
 54             bt_show_by_tree(bt_tree_a);
 55             break;
 56             case 'p':
 57             printf("please input preorder(NULL node values -1)\n");
 58             link bt_tree_b = bt_create_by_preorder();
 59             bt_show_by_tree(bt_tree_b);        
 60             break;
 61             case 'c':
 62             printf("to create complete binary tree order, assgin its length as:\n");
 63             scanf("%d", &n);
 64             printf("please input complete binary tree order(NULL node values -1)\n");
 65             for (i = 0; i < n; ++i)
 66                 scanf("%d", order+i);
 67             link bt_tree_c = bt_create_by_complete_bt_order(order, n, 0);
 68             bt_show_by_tree(bt_tree_c);
 69             break;
 70             case 'q':
 71             return 0;
 72             default:
 73             break;
 74         }
 75     }
 76     return 0;
 77 }
 78 
 79 link NODE(int item, link left, link right)
 80 {
 81     link born = malloc( sizeof (node) );
 82     born->item = item;
 83     born->left = left;
 84     born->right = right;
 85     return born;
 86 }
 87 
 88 link bt_create_by_random(int n)
 89 {
 90     srand( (unsigned)time(NULL) );
 91     return bt_create_by_random_core(n);
 92 }
 93 
 94 link bt_create_by_random_core(int n)
 95 {
 96     if (n <= 0)
 97         return NULL;
 98     if (n == 1)
 99         return NODE(rand()%MOD, NULL, NULL);
100 
101     link root = NODE(rand()%MOD, NULL, NULL);
102     int left_n = rand()%(n-1) + 1, right_n = (n-1) - left_n;
103     root->left = bt_create_by_random_core(left_n);
104     root->right = bt_create_by_random_core(right_n);
105     return root;
106 }
107 
108 link bt_create_by_preorder(void)
109 {
110     int item;
111 
112     scanf("%d", &item);
113     if (item == -1) //current root is NULL
114         return NULL;
115     link root = NODE(item, NULL, NULL);
116     root->left = bt_create_by_preorder();
117     root->right = bt_create_by_preorder();
118     return root;
119 }
120 
121 
122 link bt_create_by_complete_bt_order(int *order, int n, int idx)
123 {
124     if (order[idx] == -1 || idx >= n)
125         return NULL;
126     link root = NODE(order[idx], NULL, NULL);
127     root->left = bt_create_by_complete_bt_order(order, n, idx*2+1);
128     root->right = bt_create_by_complete_bt_order(order, n, idx*2+2);
129     return root;
130 }
131 
132 void bt_show_by_tree(link root)
133 {
134     char cmd[CMD_LEN];
135 
136     sprintf(cmd, "rm -f ./tree_src.txt");
137     system(cmd);
138 
139     FILE *fd = fopen("./tree_src.txt", "a+");
140     fprintf(fd, "\n\t\\tree");
141     tree_print(root, fd);
142     fprintf(fd, "\n\n");
143     fclose(fd);
144 
145     sprintf(cmd, "cat ./tree_src.txt | ~/tree/tree");
146     system(cmd);
147 }
148 
149 void tree_print(link root, FILE *fd)
150 {    
151     fprintf(fd, "(");
152     if (root != NULL) {
153         fprintf(fd, "%d", root->item);
154         tree_print(root->left, fd);
155         tree_print(root->right, fd);
156     }
157     fprintf(fd, ")");
158 }

 

测试示范:

ZhangHaiba-MacBook-Pro:code apple$ ./a.out
there is 3 way to create binary tree, including:
[r] create binary tree by random
[p] create binary tree by preorder(NULL node values -1)
[c] create binary tree by complete binary tree order(NULL node values -1)
[q] quit
please choice: enter charactor 'r' 'p' or 'c', or 'q' to quit
r
create binary tree with n nodes by randmon, please assgin n:
4

             19
          ___|___
          |     |
          61    49
         _|__  _|__
         |  |  |  |
         67
        _|__
        |  |

r
create binary tree with n nodes by randmon, please assgin n:
10

                  33
                 _|__
                 |  |
                 60
             ____|_____
             |        |
             80       6
            _|__   ___|___
            |  |   |     |
            43     93    54
         ___|___  _|__  _|__
         |     |  |  |  |  |
         67    31       40
        _|__  _|__     _|__
        |  |  |  |     |  |

r
create binary tree with n nodes by randmon, please assgin n:
10

             61
         ____|_____
         |        |
         11       89
        _|__   ___|___
        |  |   |     |
               34    58
              _|__  _|__
              |  |  |  |
              50
           ___|___
           |     |
           79    58
          _|__  _|__
          |  |  |  |
          81
         _|__
         |  |
         22
        _|__
        |  |

r   
create binary tree with n nodes by randmon, please assgin n:
10

                38
            ____|_____
            |        |
            38       8
           _|__  ____|____
           |  |  |       |
           54    14      62
          _|__  _|__  ___|___
          |  |  |  |  |     |
          3           68    9
         _|__        _|__  _|__
         |  |        |  |  |  |
         42
        _|__
        |  |

p
please input preorder(NULL node values -1)
89 73 -1 -1 82 92 69 -1 -1 -1 5 -1 -1

             89
         ____|____
         |       |
         73      82
        _|__  ___|___
        |  |  |     |
              92    5
             _|__  _|__
             |  |  |  |
             69
            _|__
            |  |

c
to create complete binary tree order, assgin its length as:
15
please input complete binary tree order(NULL node values -1)
89 73 82 -1 -1 92 5 -1 -1 -1 -1 69 -1 -1 -1

             89
         ____|____
         |       |
         73      82
        _|__  ___|___
        |  |  |     |
              92    5
             _|__  _|__
             |  |  |  |
             69
            _|__
            |  |

q

 

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    原文作者:张海拔
    原文地址: https://www.cnblogs.com/zhanghaiba/p/3535769.html
    本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
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