找出数组中的最大值:
double[] a = new double[N];
double aMax = a[0];
for(int i = 1; i < a.length; i++)
if(a[i] > aMax) aMax = a[i];
计算数组元素的平均值:实现思路,先求和,再计算平均值。
double[] a = new double[N];
int n = a.length;
double sum = 0.0;
for(i = 0; i < a.length; i++)
sum += a[i];
double average = sum / n
复制数组:
double[] a = new double[N];
double[] b = new double[a.length];
for(int i = 0; i < a.length; i++)
b[i] = a[i];
颠倒数组元素的顺序:
double[] a = new [N];
for(int i = 0; i < a.length/2; i++)
double temp = a[i];
a[i] = a[a.lenght-1-i];
a[a.lenght-1-i] = temp;
矩阵相乘:
double[] a = new double[N];
double[] b = new double[N];
int n = a.length;
for(int i = 0; i < n; i++)
for(int j = 0; j < n; j++)
{
//计算行i和列j的点乘
for(int k = 0; k < n; k++)
c[i][j] = a[i][k] * b[k][j]
}