A+B again

2023年3月25日 504次阅读 来源: 分支限界法

There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

InputThe input contains several test cases, please process to the end of the file.

Each case consists of two hexadecimal integers A and B in a line seperated by a blank.

The length of A and B is less than 15.OutputFor each test case,print the sum of A and B in hexadecimal in one line.

Sample Input

+A -A
+1A 12
1A -9
-1A -12
1A -AA

Sample Output

0
2C
11
-2C
-90

这个题看起来比较简单。输入两个十六进制数然后相加，但有一个问题：结果大于0的时候直接输出就可以，但结果小于0的时候要做出处理：输出它的相反数即可，只要在输出前面加-号即可。代码如下：

#include <stdio.h>

#include <stdlib.h> int main()

{

    long long int a,b,c;

    while(~scanf(“%llX%llX”,&a,&b))

    {

        c=a+b;

        if(c<0)

        {

            printf(“-%llX\n”,-c);

        }

        else printf(“%llX\n”,c);

    }

    return 0;

}

    原文作者：分支限界法
    原文地址: https://blog.csdn.net/zhuge2017302307/article/details/79184480
    本文转自网络文章，转载此文章仅为分享知识，如有侵权，请联系博主进行删除。
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