AVL树的左旋右旋、计算高度以及判断是否完全

#include <iostream>
#include <vector>
#include <queue>

using namespace std;

struct node{
	int val;
	struct node *left,*right;
};

node* leftRotate(node *tree){
	node *temp = tree->right;
	tree->right = temp->left;
	temp->left = tree;
	return temp;
}

node* righRotate(node *tree){
	node *temp = tree->left;
	tree->left = temp->right;
	temp->right=tree;
	return temp;
}

node* rightLeftRotate(node *tree) {
	tree->right = rightRotate(tree->right);
	return leftRotate(tree); 
}

node* leftRightRotate(node *tree){
	tree->left = leftRotate(tree->left);
	return rightRotate(tree);	
} 

int getHeight(node *tree){
	if(tree == NULL) return 0;
	int l = getHeight(tree->left);
	int r = getHeight(tree->right);
	return max(l,r)+1;
}

node *insert(node *tree, int val){
	if(tree ==NULL){
		tree = new Node();
		tree->val = val;
	}else if (tree->val > val){
		tree->left = insert(tree->left,val);
		int l = getHeight(tree->left),r=getHeight(tree->right);
		if(l-r>=2){
			if(val<tree->left->val)
				tree = rightRotate(tree);
			else
				tree = leftRightRotate(tree);
		}
	}else{
		tree->right = insert(tree->left,val);
		int l = getHeight(tree->left),r=getHeight(tree->right);
		if(r-l>=2){
			if(val>tree->right->val)
				tree = leftRotate(tree);
			else
				tree = rightLeftRotate(tree);
		}	
	}
	return tree;
}

int isComplete = 1, after =0;

vector<int> levelOrder(node *tree){
	vector<int> v;
	queue<node *> queue;
	queue.push(tree);
	while(!queue.empty()){
		node *temp = queue.front();
		queue.pop();
		v.push_back(temp->val);
		if(temp->left != NULL){
			if(after) isComplete = 0;
			queue.push(temp->left); 
		} else{
			after = 1;
		}
		if(temp->right != NULL){
			if(after) isComplete = 0;
			queue.push(temp->right); 
		} else{
			after = 1;
		}		
	}
	return v;
}


int main(int argc, char** argv) {
	int n,temp;
	scanf("%d",&n);
	node *tree = NULL;
	for(int i=0;i<n;i++){
		scanf("%d",&temp);
		tree = insert(tree,temp);
	}
	vector<int> v=levelOrder(tree);
	for(int i=0;i<v.size();i++){
		if(i!=0) printf(" ");
		printf("%d",v[i]);
	}
	printf("\n%s",isComplete ? "Yes": "No");
	return 0;
}

代码复制敲击自:https://www.liuchuo.net/archives/2732

    原文作者:AVL树
    原文地址: https://blog.csdn.net/hit_shaoqi/article/details/81072033
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