算法竞赛入门经典 习题3-6十进制转n进制

#include <cstdio>
#include <cstring>
int main(){
	int radix = 0;
	int dec = 0;
	int len = 0;
	char res[50];
	memset(res, '\0', sizeof(res));
	scanf("%d%d", &radix, &dec);
	while (dec > 0){
		res[len++] = dec % radix + '0';
		dec /= radix;
	}
	for (int i = len - 1; i >= 0; --i){
		printf("%c", res[i]);
	}
	printf("\n");
	return 0;
}

    原文作者:进制转换
    原文地址: https://blog.csdn.net/icehezhiyuan/article/details/24934993
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