16进制数转十进制数—实现C语言

#include<stdio.h>
#include<math.h>
double conv(char *string)
{
 double ch[10];
 int i = 0,j =0, count = 0;
 double num = 0;
 while(*(string+j) != ‘\0’)
 {
  switch(*(string+j))
  {
   case ‘A’:
    ch[j] = 10;
    break;
   case ‘B’:
    ch[j] = 11;
    break;
   case ‘C’:
    ch[j] = 12;
    break;
   case ‘D’:
    ch[j] = 13;
    break;
   case ‘E’:
    ch[j] = 14;
    break;
   case ‘F’:
    ch[j] = 15;
    break;
   default:
    ch[j] =(*(string+j) – 48);
    printf(“%d\n”,*(string+j));
  }
  j++;
  
 }

 for(i = j-1; i >=0 ; i–)
 {
  num += pow(16,i) * ch[j-i-1];
 }

 return num;
}

void main()
{
 char st[10];
 printf(“Please input a string:\n”);
 scanf(“%s”,st);
 printf(“%lf\n”,conv(st));

}



    原文作者:进制转换
    原文地址: https://blog.csdn.net/muyufenghua/article/details/14046241
    本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
点赞