用递归函数实现十进制转八进制

#include <iostream>
using namespace std;
int func(int n);
int main()
{
    int n;
    cout<<"请输入十进制正整数"<<endl;
    cin>>n;
    cout<<func(n)<<endl;
    return 0;
}
int func(int num)
{
    if(num<=8)
        return num;
    return num%8+10*func(num/8);
}