请跟着main方法走，然后看代码注释。
package hesuangyan.com.testtree;

import java.util.ArrayList;
import java.util.Iterator;
import java.util.LinkedHashMap;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;
import java.util.Set;

public class Mainin {

    static class Node {
        // 节点对象，没有按照规范封装，直接.属性即可
        String code;

        List<Node> children = new ArrayList<Node>();
        Map<String, Node> childMap = new LinkedHashMap<String, Node>();

        Node() {
            this.code = "000";
        }

        Node(String code) {
            this.code = code;
        }

        @Override
        public String toString() {
            StringBuilder str = new StringBuilder();
            return printSelf(this, str);
        }

        public String printSelf(Node n, StringBuilder str) {//输出树的json结构
            List<Node> list = n.children;
            if (list != null && list.size() > 0) {
                for (int i = 0; i < list.size(); i++) {
                    Node node = list.get(i);
                    int childeSize = node.children.size();
                    String mark = "";
                    if (childeSize != 0) {
                        mark = ":";
                    }
                    str.append("{code:" + node.code + mark);
                    printSelf(node, str);
                    str.append("}");
                    if (i + 1 != list.size()) {
                        str.append(",");
                    }
                }
            }
            return str.toString();
        }
    }

    public static void main(String[] args) {
        Node node = new Node();//
        initTreeData(node);// 构建树前的初始化平铺数据，模拟数据库查询出的数据

        Map<String, Node> rMap = new LinkedHashMap<String, Node>();// 临时组织数据map

        for (Node thisN : node.children) {
            turnToMap(rMap, thisN);// 将平铺的数据，解析到map中，构建一颗逻辑树
        }

        Node root = new Node();// 结果树
        turnToList(rMap, root);// 递归解析map树，并放入root这个根节点中
        System.out.println(root);
        // root既是结果树
    }

    static void turnToMap(Map<String, Node> rMap, Node n) {
        String key = null;
        List<String> keyList = new ArrayList<String>();
        for (int i = 0; i < n.code.length() / 3; i++) {// 组装code的父级结构
            key = n.code.substring(0, 3 + (i * 3));
            keyList.add(key);
        }

        String thisKey = null;
        Node tmpNode = null;
        Map<String, Node> tmpMap = rMap;
        for (int i = 0; i < keyList.size(); i++) {
            thisKey = keyList.get(i);
            tmpNode = tmpMap.get(thisKey);
            if (i + 1 == keyList.size()) {
                tmpMap.put(n.code, n);// 如果是末级节点，则放入该节点
            } else {
                tmpMap = tmpNode.childMap;// 如果不是末级节点，则将该节点赋值给临时变量
            }
        }
    }

    static void turnToList(Map<String, Node> rMap, Node rn) {
        Set<Entry<String, Node>> eSet = rMap.entrySet();
        Iterator<Entry<String, Node>> mIt = eSet.iterator();
        while (mIt.hasNext()) {
            Entry<String, Node> entry = mIt.next();
            Node node = entry.getValue();
            rn.children.add(node);
            turnToList(node.childMap, node);
        }
    }

    static void initTreeData(Node node) {
        node.children.add(new Node("001"));
        node.children.add(new Node("001001"));
        node.children.add(new Node("001002"));
        node.children.add(new Node("002"));
        node.children.add(new Node("002001"));
        node.children.add(new Node("002002"));
        node.children.add(new Node("002002001"));
        node.children.add(new Node("002002002"));
        node.children.add(new Node("003"));
        node.children.add(new Node("003001"));
        node.children.add(new Node("003002"));
        node.children.add(new Node("003002001"));
        node.children.add(new Node("003002002"));
        node.children.add(new Node("003002003"));
        node.children.add(new Node("003002004"));
        node.children.add(new Node("003002005"));
        node.children.add(new Node("003002006"));

        node.children.add(new Node("005"));
        node.children.add(new Node("005001"));
        node.children.add(new Node("005001002"));
        node.children.add(new Node("005001002001"));
        node.children.add(new Node("005001002002"));
    }

}