# 205. Isomorphic Strings

Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,
Given `"egg"`, `"add"`, return true.

Given `"foo"`, `"bar"`, return false.

Given `"paper"`, `"title"`, return true.

Note:
You may assume both s and t have the same length.

``````public class Solution {
/*
* 思路:利用一个Map来辅助解决问题，Map的key为s中的字符，Map的value为t中与之对应的字符
* 循环遍历s(题目中已经假设s和t长度相同),
* 		如果遍历到的字符在Map中存在，则检测它对应的value
* 是否为t中对应的字符，是则继续，不是则直接返回false；
* 		如果遍历到的字符在Map中不存在，先检测Map的vlaue中是否包含t对应的字符，如果包含
* 直接返回false，如果不包含，则将s,t中对应的字符put进Map
*
*/
public boolean isIsomorphic(String s, String t) {
if (s==null || s.length()<=1) {
return true;
}
Map<Character, Character> map = new HashMap<Character, Character>();
for (int i=0; i<s.length(); i++) {
Character a = s.charAt(i);
Character b = t.charAt(i);
if (map.containsKey(a)) {
if (map.get(a).equals(b)) {
continue;
} else {
return false;
}
} else {
if (!map.containsValue(b)) {
map.put(a, b);
} else {
return false;
}
}
}
return true;
}
}
``````