题目:
Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
解答:
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool isBalanced(TreeNode *root) {
if(root == NULL) {
return true;
}
return isBalanced(root->left) && isBalanced(root->right) && abs(getDepth(root->left) - getDepth(root->right)) <= 1;
}
int getDepth(TreeNode *root) {
if(root == NULL) {
return 0;
}
return 1 + max(getDepth(root -> left), getDepth(root -> right));
}
};
思路:按照平衡二叉树的定义:左右孩子必须都是平衡二叉树,并且左右孩子的深度最多相差1.