生成组合序列
1.递归算法
生成C(5,3)
#include <iostream>
#include <vector>
using namespace std;
vector<vector<int>> s;
vector<int> source;
void getCombination(int elementNeed, int startPos, const vector<int> &oneResult)
{
if(elementNeed == 0)
{
s.push_back(oneResult);
return;
}
while(startPos < source.size())
{
vector<int> tmp = oneResult;
tmp.push_back(source[startPos]);
getCombination(elementNeed - 1, startPos + 1, tmp);
++startPos;
}
}
int main(int argc, const char * argv[])
{
source = {1, 2, 3, 4, 5};
vector<int> tmp;
getCombination(3, 0, tmp);
for(auto k : s)
{
for(auto i : k)
{
cout << i << ' ';
}
cout << endl;
}
return 0;
}
2.非递归版本
生成C(5,3)
#include <iostream>
#include <vector>
using namespace std;
vector<vector<int>> s;
void getCombination(const vector<int> &source, int elementNeed)
{
if(elementNeed == 0)
{
return;
}
if(elementNeed > source.size())
{
return;
}
vector<int> pos;
vector<int> tmp;
for(int i = 0; i < elementNeed; ++i)
{
pos.push_back(i);
tmp.push_back(source[i]);
}
while(pos[0] + elementNeed <= source.size())
{
for(int i = 0; i < pos.size(); ++i)
{
tmp[i] = source[pos[i]];
}
s.push_back(tmp);
int k = pos.size() - 1;
while(k>0 && pos[k] + elementNeed - k == source.size()) --k;
++pos[k];
++k;
while(k < pos.size())
{
pos[k] = pos[k - 1] + 1;
++k;
}
}
}
int main(int argc, const char * argv[])
{
vector<int> source = {1, 2, 3, 4, 5};
getCombination(source, 3);
for(auto k : s)
{
for(auto i : k)
{
cout << i << ' ';
}
cout << endl;
}
return 0;
}
3.优化的非递归版本
生成C(5,3),优化减少了赋值的次数
#include <iostream>
#include <vector>
using namespace std;
vector<vector<int>> s;
void getCombination(const vector<int> &source, int elementNeed)
{
if(elementNeed == 0)
{
return;
}
if(elementNeed > source.size())
{
return;
}
vector<int> pos;
vector<int> tmp;
for(int i = 0; i<elementNeed; ++i)
{
pos.push_back(i);
tmp.push_back(source[i]);
}
while(pos[0] + elementNeed <= source.size())
{
s.push_back(tmp);
int k = pos.size() - 1;
while(k>0 && pos[k] + elementNeed - k == source.size())
{
--k;
}
++pos[k];
tmp[k] = source[pos[k]];
++k;
while(k < pos.size())
{
pos[k] = pos[k - 1] + 1;
if(pos[k] < source.size())
{
tmp[k] = source[pos[k]];
}
++k;
}
}
}
int main(int argc, const char * argv[])
{
vector<int> source = {1, 2, 3, 4, 5};
getCombination(source, 3);
for(auto k : s)
{
for(auto i : k)
{
cout << i << ' ';
}
cout << endl;
}
return 0;
}