枚举法
水题

#include <iostream>
#include <cstdio>
#include <cstdlib>
using namespace std;

const int maxn = 1000 + 5; 

int main(){
    int k,x,y,cnt;
    int xx[maxn],yy[maxn];
    bool flag;
    while(cin >> k && k!=0){
        cnt = 0;
        for(int i=k+1;i<=2*k;i++){
            flag = false;
            y = i;
            if(k*y%(y-k)==0) {
                x=k*y/(y-k);
                flag = true;
            }
            if(flag){
                xx[cnt] = x;yy[cnt] = y;cnt++;
                //printf("1/%d = 1/%d + 1/%d\n",k,x,y); 
            } 
        }
        cout<<cnt<<endl;
        for(int i=0;i<cnt;i++){
            printf("1/%d = 1/%d + 1/%d\n",k,xx[i],yy[i]);
        }
    }
    return 0;
}