Clone an undirected graph. Each node in the graph contains a label
and a list of its neighbors
.
OJ’s undirected graph serialization:
Nodes are labeled uniquely.
We use
#
as a separator for each node, and
,
as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}
.
The graph has a total of three nodes, and therefore contains three parts as separated by #
.
- First node is labeled as
0
. Connect node0
to both nodes1
and2
. - Second node is labeled as
1
. Connect node1
to node2
. - Third node is labeled as
2
. Connect node2
to node2
(itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1 / \ / \ 0 --- 2 / \ \_/
由于是无向图,所以要注意的就是要随时记录已经复制过的节点,以便加到后面节点的邻接节点指针数组中。
本题采用广度优先边访问、边复制,具体代码如下:
class Solution {
public:
UndirectedGraphNode *cloneGraph(UndirectedGraphNode *node) {
UndirectedGraphNode *result = NULL;
if(node == NULL)
return result;
unordered_set<int> S;
unordered_map<int, UndirectedGraphNode *> M;
queue<UndirectedGraphNode *> Q1, Q2;
Q1.push(node);
S.insert(node->label);
result = new UndirectedGraphNode(node->label);
Q2.push(result);
M[result->label] = result;
UndirectedGraphNode *innode, *tmpnode, *copenode;
while(!Q1.empty() && !Q2.empty())
{
innode = Q1.front();
copenode = Q2.front();
Q1.pop();
Q2.pop();
for(int i=0; i<innode->neighbors.size(); ++i)
{
if(S.find(innode->neighbors[i]->label) == S.end())
{
Q1.push(innode->neighbors[i]);
S.insert(innode->neighbors[i]->label);
tmpnode = new UndirectedGraphNode(innode->neighbors[i]->label);
M[tmpnode->label] = tmpnode;
Q2.push(tmpnode);
copenode->neighbors.push_back(tmpnode);
}
else
{
copenode->neighbors.push_back(M[innode->neighbors[i]->label]);
}
}
}
return result;
}
};