剑指offer编程题--求二叉树深度

题目描述

输入一棵二叉树,求该树的深度。从根结点到叶结点依次经过的结点(含根、叶结点)形成树的一条路径,最长路径的长度为树的深度。

思路

递归思想,分别递归求解左右子树深度,总深度=左右子树中较深的那个深度+1

Java代码

/**
public class TreeNode {
    int val = 0;
    TreeNode left = null;
    TreeNode right = null;

    public TreeNode(int val) {
        this.val = val;

    }

}
*/
public class Solution {
    public int TreeDepth(TreeNode root) {
        if(root == null){
            return 0;
        }
        int left = TreeDepth(root.left);
        int right = TreeDepth(root.right);
        return 1+(left>right?left:right);
    }
}

C++代码

/*
struct TreeNode {
    int val;
    struct TreeNode *left;
    struct TreeNode *right;
    TreeNode(int x) :
            val(x), left(NULL), right(NULL) {
    }
};*/
class Solution {
public:
    int TreeDepth(TreeNode* pRoot)
    {
        if(pRoot == NULL){
            return 0;
        }
        int ld = TreeDepth(pRoot->left);
        int rd = TreeDepth(pRoot->right);
        return 1 + (ld>rd?ld:rd);
    }
};
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