–方法0:动态SQL法
declare @s varchar(100),@sql varchar(1000)
set @s=’1,2,3,4,5,6,7,8,9,10′
set @sql=’select col=”’+ replace(@s,’,’,”’ union all select ”’)+””
PRINT @sql
exec (@sql)
if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[f_splitSTR]’) and xtype in (N’FN’, N’IF’, N’TF’))
drop function [dbo].[f_splitSTR]
GO
–方法1:循环截取法
CREATE FUNCTION f_splitSTR(
@s varchar(8000), –待分拆的字符串
@split varchar(10) –数据分隔符
)RETURNS @re TABLE(col varchar(100))
AS
BEGIN
DECLARE @splitlen int
SET @splitlen=LEN(@split+’a’)-2
WHILE CHARINDEX(@split,@s)>0
BEGIN
INSERT @re VALUES(LEFT(@s,CHARINDEX(@split,@s)-1))
SET @s=STUFF(@s,1,CHARINDEX(@split,@s)+@splitlen,”)
END
INSERT @re VALUES(@s)
RETURN
END
GO
if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[f_splitSTR]’) and xtype in (N’FN’, N’IF’, N’TF’))
drop function [dbo].[f_splitSTR]
GO
–方法2:使用临时性分拆辅助表法
CREATE FUNCTION f_splitSTR(
@s varchar(8000), –待分拆的字符串
@split varchar(10) –数据分隔符
)RETURNS @re TABLE(col varchar(100))
AS
BEGIN
–创建分拆处理的辅助表(用户定义函数中只能操作表变量)
DECLARE @t TABLE(ID int IDENTITY,b bit)
INSERT @t(b) SELECT TOP 8000 0 FROM syscolumns a,syscolumns b
INSERT @re SELECT SUBSTRING(@s,ID,CHARINDEX(@split,@s+@split,ID)-ID)
FROM @t
WHERE ID<=LEN(@s+’a’)
AND CHARINDEX(@split,@split+@s,ID)=ID
RETURN
END
GO
if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[f_splitSTR]’) and xtype in (N’FN’, N’IF’, N’TF’))
drop function [dbo].[f_splitSTR]
GO
if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[tb_splitSTR]’) and objectproperty(id,N’IsUserTable’)=1)
drop table [dbo].[tb_splitSTR]
GO
–方法3:使用永久性分拆辅助表法
–字符串分拆辅助表
SELECT TOP 8000 ID=IDENTITY(int,1,1) INTO dbo.tb_splitSTR
FROM syscolumns a,syscolumns b
GO
–字符串分拆处理函数
CREATE FUNCTION f_splitSTR(
@s varchar(8000), –待分拆的字符串
@split varchar(10) –数据分隔符
)RETURNS TABLE
AS
RETURN(
SELECT col=CAST(SUBSTRING(@s,ID,CHARINDEX(@split,@s+@split,ID)-ID) as varchar(100))
FROM tb_splitSTR
WHERE ID<=LEN(@s+’a’)
AND CHARINDEX(@split,@split+@s,ID)=ID)
GO
–方法4:利用sql server2005的OUTER APPLY
CREATE FUNCTION [dbo].[ufn_SplitStringToTable]
(
@str VARCHAR(MAX) ,
@split VARCHAR(10)
)
RETURNS TABLE
AS
RETURN
( SELECT B.id
FROM ( SELECT [value] = CONVERT(XML , ‘<v>’ + REPLACE(@str , @split , ‘</v><v>’)
+ ‘</v>’)
) A
OUTER APPLY ( SELECT id = N.v.value(‘.’ , ‘varchar(100)’)
FROM A.[value].nodes(‘/v’) N ( v )
) B
)
备注说明:
方法4必须在sql server2005下才可以运行