1、错误提示
FatalErrorException in Handler.php line 38:
Uncaught TypeError: Argument 1 passed to App\Exceptions\Handler::report() must be an instance of Exception, instance of Error given, called in D:\www\activity\vendor\compiled.php on line 1817 and defined in D:\www\activity\app\Exceptions\Handler.php:38
Stack trace:
#0 D:\www\activity\vendor\compiled.php(1817): App\Exceptions\Handler->report(Object(Error))
#1 [internal function]: Illuminate\Foundation\Bootstrap\HandleExceptions->handleException(Object(Error))
#2 {main}
thrown
原因:D:wwwactivityvendorcompiled.php on line 1817 的变量$e不是Exception的实例对象(对错误提示的翻译……^.^笑cry)
2、解决方案
在提示的错误地方加上变量$e的实例判断,如果不是Exception类型,就new一个
if (!$e instanceof \Exception) {
$e = new FatalThrowableError($e);
}
new完之后的样子:
public function handleException($e)
{
if (!$e instanceof \Exception) {
$e = new FatalThrowableError($e);
}
$this->getExceptionHandler()->report($e);
if ($this->app->runningInConsole()) {
$this->renderForConsole($e);
} else {
$this->renderHttpResponse($e);
}
}