sql 查出一张表中重复的所有记录数据

1、在面试的时候碰到一个 问题,就是让写一张表中有id和name 两个字段,查询出name重复的所有数据,现在列下:

select * from xi a where (a.username) in  (select username from xi group by username  having count(*) > 1)

2、查询出所有数据进行分组之后,和重复数据的重复次数的查询数据,先列下:

select  count(username) as '重复次数',username from xi group by username  having count(*)>1 order by username desc

3、一下为 查看别人的 结果,现列下:查询及删除重复记录的方法大全

1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断

select * from people
where peopleId in (select  peopleId  from  people  group  by  peopleId  having  count(peopleId) > 1)

2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录

delete from people 
where peopleId  in (select  peopleId  from people  group  by  peopleId   having  count(peopleId) > 1)
and rowid not in (select min(rowid) from  people  group by peopleId  having count(peopleId )>1)

另外,MySQL中使用上面的SQL会报错:You can’t specify target table ‘XXX’ for update in FROM clause,不能在修改表的同时去查询同一张表,因此可以像下面的语句一样,将查询结果命名为一张临时表来作为修改表数据的条件,以规避上述错误。

delete from user where user_id in(
    (select user_id from 
        (select c.* from cab_user c where c.extra_id in 
            (select  a.extra_id  from user a group  by  a.extra_id having  count(a.extra_id) > 1) and c.user_id not in 
            (select min(b.user_id) from  user b group by b.extra_id having count(b.extra_id )>1)
        ) d
    )
)

3、查找表中多余的重复记录(多个字段)

select * from vitae a
where (a.peopleId,a.seq) in  (select peopleId,seq from vitae group by peopleId,seq  having count(*) > 1)

4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录

delete from vitae a
where (a.peopleId,a.seq) in  (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录

select * from vitae a
where (a.peopleId,a.seq) in  (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

(二)
比方说
在A表中存在一个字段“name”,
而且不同记录之间的“name”值有可能会相同,
现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;

Select Name,Count(*) From A Group By Name Having Count(*) > 1

如果还查性别也相同大则如下:

Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1

(三)
方法一declare @max integer,@id integerdeclare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1open cur_rowsfetch cur_rows into @id,@maxwhile @@fetch_status=0beginselect @max = @max -1set rowcount @maxdelete from 表名 where 主字段 = @idfetch cur_rows into @id,@maxendclose cur_rowsset rowcount 0

方法二"重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。

  1、对于第一种重复,比较容易解决,使用select distinct * from tableName  就可以得到无重复记录的结果集。  如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除select distinct * into #Tmp from tableNamedrop table tableNameselect * into tableName from #Tmpdrop table #Tmp  发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。

  2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下  假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集select identity(int,1,1) as autoID, * into #Tmp from tableNameselect min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoIDselect * from #Tmp where autoID in(select autoID from #tmp2)  最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)

(四)
查询重复

select * from tablename where id in (select id from tablenamegroup by idhaving count(id) > 1)

文章转自:http://blog.csdn.net/a1108501…

    原文作者:mid_summer
    原文地址: https://segmentfault.com/a/1190000007487448
    本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
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