1. 题目

Given an array of strings, group anagrams together.

For example, given: [“eat”, “tea”, “tan”, “ate”, “nat”, “bat”],
Return:

[
[“ate”, “eat”,”tea”],
[“nat”,”tan”],
[“bat”]
]
Note: All inputs will be in lower-case.

2. 思路

对每一个字符串a，对齐排序得到b，建立一个<b,a>的映射，对所有key相同的多个a合并起来即可。实现时用<sort_string, vector<string_raw>>来完成。

3. 代码

耗时：75ms

class Solution {
public:
    // 将string的排序结果作为key, 建立<k,list>结果
    vector<vector<string>> groupAnagrams(vector<string>& strs) {
        unordered_map<string, vector<string>> map;
        for (int i = 0; i < strs.size(); i++) {
            string s_dup = strs[i];
            sort(s_dup.begin(), s_dup.end());
            auto it = map.find(s_dup);
            if (it == map.end()) {
                vector<string> first;
                first.push_back(strs[i]);
                map[s_dup] = first;
            } else {
                it->second.push_back(strs[i]);
            }
        }
        vector<vector<string>> ret;
        for (auto it = map.begin(); it != map.end(); it++) {
            ret.push_back(it->second);
        }
        return ret;
    }
};