LeetCode 162 Find Peak Element

题目描述

A peak element is an element that is greater than its neighbors.

Given an input array where num[i] ≠ num[i+1], find a peak element and return its index.

The array may contain multiple peaks, in that case return the index to any one of the peaks is fine.

You may imagine that num[-1] = num[n] = -∞.

For example, in array [1, 2, 3, 1], 3 is a peak element and your function should return the index number 2.

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Note:
Your solution should be in logarithmic complexity.

分析

要log的时间复杂度,要用到二分查找。

代码

    public static int findPeakElement(int[] nums) {

        int low = 0;
        int high = nums.length - 1;

        while (low < high) {
            int mid = low + (high - low) / 2;
            if (nums[mid] > nums[mid + 1]) {
                high = mid;
            } else {
                low = mid + 1;
            }
        }

        return low;
    }
    原文作者:_我们的存在
    原文地址: https://blog.csdn.net/Yano_nankai/article/details/50155977
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