int getTreeDepth(treeNode *pRoot){
if(pRoot == NULL){
return 0;
}
int left = getTreeDepth(pRoot->pLeft);
int right = getTreeDepth(pRoot->pRight);
return left > right ? left+1 : right+1;
}
bool isBalanceTree(treeNode *pRoot){
if(pRoot == NULL){
return true;
}
int left = getTreeDepth(pRoot->pLeft);
int right = getTreeDepth(pRoot->pRight);
int diff = left-right;
if(diff > 1 || diff < -1){
return true;
}
return isBalanceTree(pRoot->pLeft) && isBalanceTree(pRoot->pRight);
}
bool isBalanceTree01(treeNode *pRoot, int &depth){
if(pRoot == NULL){
depth = 0;
return true;
}
int left;
int right;
if(isBalanceTree(pRoot->pLeft, &left) && isBalanceTree(pRoot->pRight, &right)){
int diff = left-right;
if(diff < 1 && diff > -1){
depth = left > right ? left+1 : right+1;
return true;
}
}
return false;
}
C语言 判断二叉树是不是平衡树
原文作者:平衡二叉树
原文地址: https://blog.csdn.net/bad7code/article/details/46443865
本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
原文地址: https://blog.csdn.net/bad7code/article/details/46443865
本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。