[leetcode] wordsearch

problem: https://oj.leetcode.com/problems/word-search/
代码:https://play.golang.org/p/d5wP691Pbg

package main

import (
    "fmt"
)

func main() {
    arr := [][]byte{
        {'A', 'B', 'C', 'E'},
        {'S', 'F', 'C', 'S'},
        {'A', 'D', 'E', 'E'},
    }
    //word := []byte("ABCESC")
    word := []byte("SFCE")
    arrI, arrJ, ok := FindFirstCharPositions(arr, word[0])
    if ok {
        fmt.Printf("%d, %d\n", arrI, arrJ)
    }
    fmt.Println(DFSTraverse(arr, word, arrI, arrJ))
}

func DFSTraverse(arr [][]byte, word []byte, arrI []int, arrJ []int) (ret bool) {
    //初始化visited函数
    lenArr := len(arr)
    visited := make([][]bool, lenArr)
    for i := 0; i < lenArr; i++ {
        visited[i] = make([]bool, len(arr[i]))
    }
    lenArrI := len(arrI)
    //lenArrJ := len(arrJ)
    for i := 0; i < lenArrI; i++ {
        //fmt.Println(i)
        ret = DFS(arr, word, 0, visited, arrI[i], arrJ[i])
        if ret == true {
            return true
        }
    }
    return
}

//dfs traverse, when found return true
func DFS(arr [][]byte, word []byte, index int, visited [][]bool, i int, j int) (ret bool) {
    if i < 0 || j < 0 || i >= len(visited) || j >= len(visited[i]) || visited[i][j] {
        return false
    }
    if index == len(word) {
        return true
    }
    if arr[i][j] != word[index] {
        return false
    }

    fmt.Printf("%c:%d,%d ", word[index], i, j)
    visited[i][j] = true //标识为已访问
    index++
    //fmt.Println("yes")
    ret = DFS(arr, word, index, visited, i-1, j) ||
        DFS(arr, word, index, visited, i, j+1) ||
        DFS(arr, word, index, visited, i+1, j) ||
        DFS(arr, word, index, visited, i, j-1)
    visited[i][j] = false
    return ret
}

func FindFirstCharPositions(arr [][]byte, c byte) (arrI []int, arrJ []int, ok bool) {
    lenArrRow := len(arr)
    if lenArrRow == 0 {
        return
    }
    lenArrCol := len(arr[0])

    for i := 0; i < lenArrRow; i++ {
        for j := 0; j < lenArrCol; j++ {
            if arr[i][j] == c {
                arrI = append(arrI, i)
                arrJ = append(arrJ, j)
                ok = true
            }
        }
    }
    return
}

    原文作者:MrRightLeft_秦磊
    原文地址: https://segmentfault.com/a/1190000002391006
    本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
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