private static class ListNode {
public int value;
public ListNode next = null;
}
private static class TreeNode {
public int value;
public TreeNode left = null;
public TreeNode right = null;
}
private static TreeNode convertList2Tree(ListNode head, int length) {
if (head == null || length == 0) return null;
ListNode leftHead = null, rootHead = null, rightHead = null;
TreeNode leftRoot = null, root = null, rightRoot = null;
if (length % 2 == 1) {
// 1 2 3 [4] 5 6 7
leftHead = head;
rootHead = moveList(leftHead, length / 2 + 1);
rightHead = rootHead.next;
leftRoot = convertList2Tree(leftHead, length / 2);
rightRoot = convertList2Tree(rightHead, length / 2);
} else {
// 0 1 2 [3] 4 5
leftHead = head;
rootHead = moveList(leftHead, length / 2 + 1);
rightHead = rootHead.next;
leftRoot = convertList2Tree(leftHead, length / 2);
rightRoot = convertList2Tree(rightHead, length / 2 - 1);
}
root = new TreeNode();
root.left = leftRoot;
root.right = rightRoot;
root.value = rootHead.value;
return root;
}
有序链表转BST(平衡查找二叉树)
原文作者:二叉查找树
原文地址: https://blog.csdn.net/qq_17612199/article/details/52671411
本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
原文地址: https://blog.csdn.net/qq_17612199/article/details/52671411
本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。