lodash中文文档如今我只找到了3.10.x版本，如今lodash已更新到4.17.x了，很多文档已逾期。而且lodash中api太多，有时候经常运用的几个我老是记不住名字，在这里贴出来，轻易本身和人人。

原生用法

直接运用的API

_.reject

依据前提去除某个元素。

var foo = [
    {id: 0, name: "aaa", age: 33},
    {id: 1, name: "bbb", age: 25}
]
var bar = _.reject(foo, ['id', 0])

//bar = [{id: 1, name: "bbb", age: 25}]

_.pick

依据第二个参数的key的数组，挑选第一个参数中的值并返回

var foo = {id: 0, name: "aaa", age: 33}
var bar = _.pick(foo, ['name', 'age'])
//bar = {name: "aaa", age: 33}

_.keys

返回object中的一切key

var foo = {id: 0, name: "aaa", age: 33}
var bar = _.keys(foo)
//bar = ['id', 'name', 'age']

_.cloneDeep

深度拷贝，这个不必多说了吧，js中基本范例之外的范例，都邑默许拷贝备份
var bar = _.cloneDeep(foo)

_.find

查找数组

var foo = [
    {id: 0, name: "aaa", age: 33},
    {id: 1, name: "bbb", age: 25}
]
var bar = _.find(foo, ['id', 0])
//bar = {id: 0, name: "aaa", age: 33}

注重一下假如没找到的话，会返回undefined，要处置惩罚一下

_.keyBy

以某个属性为键，将数组转为对象

var foo = var foo = [
    {id: 0, name: "aaa", age: 33},
    {id: 1, name: "bbb", age: 25}
]
var bar = _.keyBy(foo, 'name')
//bar = {
//    aaa: {id: 0, name: "aaa", age: 33},
//    bbb: {id: 1, name: "bbb", age: 25}
//}

_.filter

依据前提过滤出相符前提的元素，返回新数组

var foo = var foo = [
    {id: 0, name: "aaa", age: 33},
    {id: 1, name: "bbb", age: 25}
]
var bar = _.filter(foo, ['name', "aaa"])
//bar = [{id: 0, name: "aaa", age: 33}]

_.map

从鸠合中挑出一个key，将其值作为数组返回

var foo = var foo = [
    {id: 0, name: "aaa", age: 33},
    {id: 1, name: "bbb", age: 25}
]
var bar = _.map(foo, 'name')
//bar = ["aaa", "bbb"]

_.max/_.min/_.sum

数组中最大值、最小值、数组乞降

var foo = [1, 2, 3, 4]
var bar = _.max(foo)
//bar = 4
bar = _.min(foo)
//bar = 1
bar = _.sum(foo)
//bar = 10

_.pad/_.padStart/_.padEnd

在两头、开首、末端补齐字符

var foo = "helloworld"
var bar = _.pad(foo, 14, '-')
//bar = --helloworld--
bar = _.padStart(foo, 14, '-')
//bar = ----helloworld
bar = _.padEnd(foo, 14, '-')
//bar = helloworld----

组合用法

假如说上面是基本妙技，那末下面送上几个炫酷的组合技：

选出json数组中id最大的一项

var foo = [
    {id: 0, name: "aaa", age: 33},
    {id: 1, name: "bbb", age: 25}
]
var bar = _.find(foo, ['id', _.max(_.map(foo, 'id'))])
// bar = {id: 1, name: "bbb", age: 25}

ps:也可以用maxBy某个key来替代

更新json数组中某一项的值

var foo = [
    {id: 0, name: "aaa", age: 33},
    {id: 1, name: "bbb", age: 25}
]
let list = _.keyBy(foo, 'id')
list[0].name = "ccc"
var bar = _.map(list)
// bar = [
//    {id: 0, name: "ccc", age: 33},
//    {id: 1, name: "bbb", age: 25}
//]