题目意思就是给你一个满二叉树，然后输入命令查询，0是向左，1是向右。比较简单，直接上代码。

#include<iostream>
#include <string>
#include <string.h>
using namespace std;

int lefttree[1000],righttree[1000]; int n;
string st; int countindex = 0; int xn[1000]; int a[1000]; int zeroOrone = 0; char console[1000]; int kase = 0;
int square(int v, int c) {
	int sum = 1;
	for (int i = 0; i < c; i++) {
		sum = sum * v;
	}
	return sum;
}
void readInput(int n) {
	memset(lefttree, 0, sizeof(lefttree));
	memset(righttree, 0, sizeof(righttree));
	countindex = 0;
	char s[3];
	for (int i = 0; i < n; i++) {
		cin >> s;
		xn[i] = s[1]-'0';
	}
	cin >> st;
	for (int i = 1; i <= square(2,n-1)-1; i++) {
		lefttree[i] = i * 2;
		righttree[i] = i * 2 + 1;
	}
	
}
void getvalue(int u){
		int leftindex0 = lefttree[u];
		int rightindex0 = righttree[u];
		if (leftindex0 == 0&&rightindex0== 0) {
			lefttree[u] = st[countindex++]-'0'; righttree[u]=st[countindex++]-'0';
			return;
		}
		getvalue(leftindex0);
		getvalue(rightindex0);
}
bool isflag = false;
void treeFindOrder(int u,int c) {
	if (c == -1&&!isflag) {
		zeroOrone = u; 
		isflag = true;
		return;
	}
	if(a[c]==0){ 
		int leftindex0 = lefttree[u]; treeFindOrder(leftindex0, --c);
	}
	if (a[c] == 1) {
		int rightindex0 = righttree[u]; treeFindOrder(rightindex0, --c);
	}
}
void getorder() {
	int d; string s;
	cin >> d;
	for (int i = 0; i < d; i++) {
		cin >> s;
		for (int i = 0; i < n; i++) {
			a[n-1-i] = s[xn[i]-1]-'0';
		}
		//遍历树
		isflag = false;
		treeFindOrder(1, n - 1);
		char xr = zeroOrone + '0';
		console[i] = xr;
	}
	printf("S-Tree #%d:\n", kase);
	for(int i=0;i<d;i++)
	cout << console[i];
	cout << endl<<endl;
}
int main()
{
   while (cin >> n && n) {
	kase++;
	readInput(n);
	getvalue(1);
	getorder();
   }
	return 0;
}