更新:
谢谢 @行列[xxooyy] 给了一个越发精简的要领完成:
String.prototype.toFunction=function(){ return eval('('+this+')')};
//重点在'('和')'
String.prototype.toFunction = function () {
var fnString = this.toString();
var preRs = "^function\\s*[a-zA-Z]*?\\([\\s\\S]*?\\)\\s*\\{";
var endRs = "\\}$";
var argRs = "^function\\s*[a-zA-Z]*?\\(|\\)\\s*\\{|\\s*";
var preReg = new RegExp(preRs, 'i');
var endReg = new RegExp(endRs);
var argReg = new RegExp(argRs, 'g');
var preEndReg = new RegExp(preRs + '|' + endRs, 'gi');
if (preReg.test(fnString)) {
var preEnd = fnString.match(preEndReg);
var fnArguments = preEnd[0].replace(argReg, '').split(',');
var fnBody = fnString.replace(preEndReg, '');
var fn = new Function(fnArguments, fnBody);
return fn;
} else {
return fnString;
}
}
'function (a) { console.log(a); }'.toFunction();
//function anonymous(a) { console.log(a); }
要领很愚笨,不知道有无大神给改改的,或许有什么可替代的体系要领。
https://jsfiddle.net/jsoncode…
总结一行奇异的代码:
var fn = function (){};
new Function('return '+Function.prototype.toString.call(fn));
//会复原到fn