遍历多叉树(递归、非递归广度优先、深度优先)

简朴的遍历一个树形构造数据的几种要领、非递归要领效力最好。

(function (window, undefined) {
    var treeNodes = [
       {
            id: 1,
            name: '1',
            children: [
                 {
                      id: 11,
                      name: '11',
                      children: [
                           {
                                id: 111,
                                name: '111',
                                children:[]
                           },
                           {
                                id: 112,
                                name: '112'
                           }
                      ]
                 },
                 {
                      id: 12,
                      name: '12',
                      children: []
                 }
            ],
            users: []
       },
       {
            id: 2,
            name: '2',
            children: [
                {
                    id: 22,
                    name: '22',
                    children: []
                }
            ]
       }
    ];

    //递归完成
    var parseTreeJson = function(treeNodes){
       if (!treeNodes || !treeNodes.length) return;

       for (var i = 0, len = treeNodes.length; i < len; i++) {

            var childs = treeNodes[i].children;

            console.log(treeNodes[i].id);

            if(childs && childs.length > 0){
                 parseTreeJson(childs);
            }
       }
    };

    console.log('------------- 递归完成 ------------------');
    parseTreeJson(treeNodes);

    //非递归广度优先完成
    var iterator1 = function (treeNodes) {
        if (!treeNodes || !treeNodes.length) return;

        var stack = [];

        //先将第一层节点放入栈
        for (var i = 0, len = treeNodes.length; i < len; i++) {
            stack.push(treeNodes[i]);
        }

        var item;

        while (stack.length) {
            item = stack.shift();

            console.log(item.id);

            //假如该节点有子节点,继承增加进入栈底
            if (item.children && item.children.length) {
                //len = item.children.length;

                // for (i = 0; i < len; i++) {
                //  stack.push(item.children[i]);
                // }

                stack = stack.concat(item.children);
            }
        }
    };

    console.log('------------- 非递归广度优先完成 ------------------');
    iterator1(treeNodes);

    //非递归深度优先完成
    var iterator2 = function (treeNodes) {
        if (!treeNodes || !treeNodes.length) return;

        var stack = [];

        //先将第一层节点放入栈
        for (var i = 0, len = treeNodes.length; i < len; i++) {
            stack.push(treeNodes[i]);
        }

        var item;

        while (stack.length) {
            item = stack.shift();

            console.log(item.id);

            //假如该节点有子节点,继承增加进入栈顶
            if (item.children && item.children.length) {
                // len = item.children.length;

                // for (; len; len--) {
                //  stack.unshift(item.children[len - 1]);
                // }
                stack = item.children.concat(stack);
            }
        }
    };

    console.log('------------- 非递归深度优先完成 ------------------');
    iterator2(treeNodes);
})(window);
    原文作者:邓木琴居然被盗用了
    原文地址: https://segmentfault.com/a/1190000003004435
    本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
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