d3.js[v4] 直方图规划

2024年3月9日 304次阅读 来源: 梵鹿

直方图规划

直方图规划能够用来示意数据散布，经由过程将离散数据点分组归纳到矩形条里绘制。

数据

//运用自力变量数为10的贝茨散布随机数天生器天生1000个0～1之间的数字
var data = d3.range(1000).map(d3.randomBates(10));

定义两个映照坐标比例尺

var x = d3.scaleLinear()
    .rangeRound([0, width]);
    

var y = d3.scaleLinear()
    .domain([0, d3.max(bins, function(d) { return d.length; })])
    .range([height, 0]);

用直方图规划转换数据

var bins = d3.histogram()
    .domain(x.domain())
    .thresholds(x.ticks(20))
    (data);

绑定数据绘制矩形和文本

<!DOCTYPE html>
<meta charset="utf-8">
<style>

.bar rect {
  fill: steelblue;
}

.bar text {
  fill: #fff;
  font: 10px sans-serif;
}

</style>
<svg width="960" height="500"></svg>
<script src="https://d3js.org/d3.v4.min.js"></script>
<script>

var data = d3.range(1000).map(d3.randomBates(10));

var formatCount = d3.format(",.0f");

var svg = d3.select("svg"),
    margin = {top: 10, right: 30, bottom: 30, left: 30},
    width = +svg.attr("width") - margin.left - margin.right,
    height = +svg.attr("height") - margin.top - margin.bottom,
    g = svg.append("g").attr("transform", "translate(" + margin.left + "," + margin.top + ")");

var x = d3.scaleLinear()
    .rangeRound([0, width]);

var bins = d3.histogram()
    .domain(x.domain())
    .thresholds(x.ticks(20))
    (data);

var y = d3.scaleLinear()
    .domain([0, d3.max(bins, function(d) { return d.length; })])
    .range([height, 0]);

var bar = g.selectAll(".bar")
  .data(bins)
  .enter().append("g")
    .attr("class", "bar")
    .attr("transform", function(d) { return "translate(" + x(d.x0) + "," + y(d.length) + ")"; });

bar.append("rect")
    .attr("x", 1)
    .attr("width", x(bins[0].x1) - x(bins[0].x0) - 1)
    .attr("height", function(d) { return height - y(d.length); });

bar.append("text")
    .attr("dy", ".75em")
    .attr("y", 6)
    .attr("x", (x(bins[0].x1) - x(bins[0].x0)) / 2)
    .attr("text-anchor", "middle")
    .text(function(d) { return formatCount(d.length); });

g.append("g")
    .attr("class", "axis axis--x")
    .attr("transform", "translate(0," + height + ")")
    .call(d3.axisBottom(x));

</script>
    原文作者：梵鹿
    原文地址: https://segmentfault.com/a/1190000014000414
    本文转自网络文章，转载此文章仅为分享知识，如有侵权，请联系博主进行删除。
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