11. Container With Most Water

欢迎fork and star:Nowcoder-Repository-github

11. Container With Most Water

题目

Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container and n is at least 2. 

解析

  • 再次体会到双指针操作的厉害了
  • 理解题意为什么++–就可以实现取最大的容器,容器的面积由短板决定!!!

// 11. Container With Most Water 
class Solution_11 {
public:
    int maxArea(vector<int> &height) {
        int start = 0;
        int end = height.size() - 1;

        int max_area = 0;
        while (start<end)
        {
            max_area = max(max_area, min(height[start],height[end])*(end-start) );
            if (height[start]<=height[end]) 
            {
                start++;
            }
            else
            {
                end--;
            }
        }
        return max_area;
    }
};

题目来源

    原文作者:ranjiewen
    原文地址: https://www.cnblogs.com/ranjiewen/p/8312664.html
    本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
点赞