在element-ui的el-tree树形控件中默许猎取拔取当前选中id的要领是this.$refs.tree.getCheckedKeys();
然则如果子节点不是悉数选中的话,父节点算不选中。
因为我们平常想要的是就算只选中一个直接点父节点以及其父辈都算选中,所以须要本身写逻辑。
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>树形列表</title>
<!-- 引入款式 -->
<link rel="stylesheet" href="https://unpkg.com/element-ui/lib/theme-chalk/index.css">
<style>
[v-cloak] {
display: none;
}
</style>
</head>
<body>
<div id="app" v-cloak>
<el-tree
:data="rootData"
ref="rootTree"
show-checkbox
node-key="value"
default-expand-all>
</el-tree>
<button @click="getKeys">猎取选中节点Key</button>
</div>
<script src="https://unpkg.com/vue/dist/vue.js"></script>
<script src="https://unpkg.com/element-ui/lib/index.js"></script>
<script>
new Vue({
el: '#app',
data: {
message: 'Hello',
rootData: [{"value":16,"label":"首页","parent":-1},{"value":17,"label":"用户列表","parent":-1},{"value":18,"label":"信息列表","parent":18},{"value":19,"label":"信息治理","parent":-1,"children":[{"value":20,"label":"个人信息","parent":19},{"value":21,"label":"修正信息","parent":19}]},{"value":22,"label":"资金数据","parent":-1,"children":[{"value":23,"label":"投资散布","parent":22},{"value":24,"label":"项目散布","parent":22},{"value":25,"label":"收支统计","parent":22}]},{"value":26,"label":"体系治理","parent":26,"children":[{"value":27,"label":"机构治理","parent":26},{"value":28,"label":"角色治理","parent":26},{"value":29,"label":"岗亭治理","parent":26},{"value":30,"label":"用户治理","parent":26},{"value":31,"label":"体系菜单","parent":26}]},{"value":32,"label":"车辆治理","parent":-1,"children":[{"value":33,"label":"车辆信息","parent":32}]}]
},
methods: {
getKeys () {
var aKey = this.getCheckedKeys(this.rootData, this.$refs.rootTree.getCheckedKeys(), 'value');
console.log(aKey);
},
getCheckedKeys (data, keys, key) {
var res = [];
recursion(data, false);
return res;
// arr -> 树形总数据
// keys -> getCheckedKeys猎取到的选中key值
// isChild -> 用来推断是不是是子节点
function recursion (arr, isChild) {
var aCheck = [];
for ( var i = 0; i < arr.length; i++ ) {
var obj = arr[i];
aCheck[i] = false;
if ( obj.children ) {
aCheck[i] = recursion(obj.children, true) ? true : aCheck[i];
if ( aCheck[i] ) {
res.push(obj[key]);
}
}
for ( var j = 0; j < keys.length; j++ ) {
if ( obj[key] == keys[j] ) {
aCheck[i] = true;
if ( res.indexOf(obj[key]) == -1 ) {
res.push(obj[key]);
}
break;
}
}
}
if ( isChild ) {
return aCheck.indexOf(true) != -1;
}
}
}
}
})
</script>
</body>
</html>
getCheckedKeys函数用来猎取选中的node-key指向的键值。