10以内的加法

设计一个程序，帮助小学生练习10以内的加法

详情: 
    - 随机生成加法题目;
    - 学生查看题目并输入答案;
    - 判别学生答题是否正确?
    - 退出时, 统计学生答题总数,正确数量及正确率(保留两位小数点)；

import random
num = 0 
for i in range(11):
    x = random.randint(0,10)
    y = random.randint(0,10)
    print("%d+%d=" %(x,y),end='')
    val=int(input())
    if val == (x+y):
        num+=1
        print("true")
    else:
        print("false")

    D=float(num/10)*100
print("percent:%.2f%%" %(D))
                              

四则运算

小学生算术能力测试系统:

设计一个程序，用来实现帮助小学生进行百以内的算术练习，它具有以下功能：提供10道加、减、乘或除四种基本算术运算的题目；练习者根据显示的题目输入自己的答案，程序自动判断输入的答案是否正确并显示出相应的信息。

import random

op = ['+', '-', '*', '/']
count = 0
for i in range(1, 11):

    s = random.choice(op)
    if s == '+':
        num1 = random.randint(0, 101)
        num2 = random.randint(0, 101)
        result = num1 + num2
        print("the %d question: %d + %d" % (i, num1, num2), end='')
        result1 = int(input(' = '))
        print(result == result1)
        if result == result1:
            count += 1
    elif s == '-':
        num1 = random.randint(0, 101)
        num2 = random.randint(0, 101)
        maxnum  = num1 if num1>num2 else num2
        minnum  = num1 if num1<num2 else num2
        result = maxnum - minnum
        print("the %d question: %d - %d" % (i, num1, num2), end='')
        result1 = int(input(' = '))
        print(result == result1)
        if result == result1:
            count += 1
    elif s == '*':
        num1 = random.randint(0, 11)
        num2 = random.randint(0, 11)
        result = num1 * num2
        print("the %d question: %d * %d" % (i, num1, num2), end=':')
        result1 = int(input(' = '))
        print(result == result1)
        if result == result1:
            count += 1
    else:
        num1 = random.randint(0, 11)
        num2 = random.randint(1, 11)
        result = int(num1 / num2)
        print("the %d question: %d / %d" % (i, num1, num2), end='')
        result1 = int(input(' = '))
        print(result == result1)
        if result == result1:
            count += 1
print(count)
percent = (count / 10) * 100
print('right percent = %.2f%%' % (percent))

算法之指定范围内判断

1). 若一个正整数n的所有小于n的因子之和等于n, 则称n为完全数, 如6=1+2+3是完全数。判断正整数n是否为完全数。

num = int(input("请输入你所要判断的数："))
spectors=[]
sum = 0
for i in range(1,num):
        if (num % i) ==0:
                spectors.append(i)
                sum = sum + i
if sum == num:
        print("%s is a perfect number" %(num))
        print("%s have factors:" %(num),end=':' )
        print(spectors[:])

else:
        print('%s is not a perfect number' % (num))

2). 输入一个正整数，判断其是否为一个素数

num2=int(input('please input a number:'))
valse=[]
for i in range(1,num2+1):
        if (num2 % i) == 0:
                valse.append(i)

if valse==[1,num2]:
        print('%s is a prime number' %(num2))
else:
        print("%s is not a prime number" %(num2))

3). 输入一个正整数，判断其是否为一个回文数（例1221、12321都是回文数）；

num3=input('please input a number:')
if num3[:]==num3[::-1]:
        print('%s is a palindromic number' %(num3))
else:
        print('%s is not a palindromic number' %(num3))

累加和类型程序:

1). 求f=1+2+...+9【很简单的问题】
    

num = 0
for i in range(10):
    num = i +num
print(num)

2). 求f=1-2+3-4+...+9【在（一）的基础上，学习如何一正一负地累加】

num = 0
for i in range(1,10,2):
    num = i +num
for i in range(2,10,2):
    num = num -i
print(num)

3). 求f=1-1/2+1/3-1/4+...+1/9【在（二）的基础上，被加数成了自然数的倒数】

num = 0
for i in range(1,10,2):
    num = (1/i) +num
for i in range(2,10,2):
    num = num -(1/i)
print(num)

4). 求f=1!-2!+3!-4!+...+9!【在（二）的基础上，被加数成了自然数的阶乘】