我已经使一个类的成员不可复制,但我给它一个移动构造函数和赋值运算符.然而它不能用像矢量那样的容器来打球.
class NonCopyable
{
public:
NonCopyable(const NonCopyable&) = delete;
NonCopyable& operator=(const NonCopyable&) = delete;
protected:
NonCopyable()
{
}
~NonCopyable() _NOEXCEPT
{
}
};
class Member : NonCopyable
{
public:
Member(int i) : mNum(i)
{
}
~Member()
{
}
Member(Member&& other) _NOEXCEPT : mNum(other.mNum)
{
}
Member& operator= (Member&& other) _NOEXCEPT
{
std::swap(mNum, other.mNum);
return *this;
}
private:
int mNum;
};
struct Item
{
Item(int i) : mMember(i)
{
}
Member mMember;
};
int _tmain(int argc, _TCHAR* argv[])
{
std::vector<Item> vec;
vec.emplace_back(1);
return 0;
}
以下编译错误:
error C2280: 'NonCopyable::NonCopyable(const NonCopyable &)' : attempting to reference a deleted function
see declaration of 'NonCopyable::NonCopyable'
This diagnostic occurred in the compiler generated function 'Member::Member(const Member &)'
为什么编译器不能识别会员可以被移动?我错过了什么?
编辑:Visual Studio 2013
EDIT2:我将它添加到Item并编译:
Item(Item&& other) _NOEXCEPT : mMember(std::move(other.mMember))
{
}
我还好吗?是吗?
最佳答案 在VS2013中,部分实现了默认和删除的函数和右值引用.升级到VS2015,根据Microsoft完全实现这些功能(您的示例编译正常).
C++11/14/17 Features In VS 2015 RC