sql – 连接两个层次结构查询以形成更大的层次结构

2023年11月10日 139次阅读

我已经研究了这个,知道我不是第一个要问的人,但我似乎无法理解它.我创建了一个简单的例子,如果有人可以提供缺失的链接,我认为这将帮助我破解它！

我有一个包含大陆和等级国家/地区的区域的表格.

我还有一个地方表,其中包含层次结构中的城市和地标.此表包含要加入区域表的区域ID列.

    create table areas
(
  id            NUMBER not null,
  name          VARCHAR2(200) not null,
  parent_id     NUMBER
);

-- Top Level
Insert into areas (id, name)
 Values (1, 'Europe');
Insert into areas (id, name)
 Values (2, 'Americas');
Insert into areas (id, name)
 Values (3, 'Asia ex Japan');
Insert into areas (id, name)
 Values (4, 'Japan');

 -- Jurisdictions
Insert into areas (id, name, parent_id)
 Values (5, 'UK', 1);
Insert into areas (id, name, parent_id)
 Values (7, 'France', 1);
Insert into areas (id, name, parent_id)
 Values (6, 'Germany', 1);
Insert into areas (id, name, parent_id)
 Values (8, 'Italy', 1);
Insert into areas (id, name, parent_id)
 Values (9, 'US', 2);
Insert into areas (id, name, parent_id)
 Values (10, 'Australia', 3);
Insert into areas (id, name, parent_id)
 Values (11, 'New Zealand', 3);

create table places
(
  id            NUMBER not null,
  name          VARCHAR2(200) not null,
  area_id       NUMBER,
  parent_id     NUMBER
);

Insert into places (id, name, area_id, parent_id)
 Values (1, 'London', 5, NULL);
Insert into places (id, name, area_id, parent_id)
 Values (2, 'Bath', 5, NULL);
Insert into places (id, name, area_id, parent_id)
 Values (3, 'Liverpool', 5, NULL);
Insert into places (id, name, area_id, parent_id)
 Values (4, 'Paris', 7, NULL);
Insert into places (id, name, area_id, parent_id)
 Values (5, 'New York', 9, NULL);
Insert into places (id, name, area_id, parent_id)
 Values (6, 'Chicago', 9, NULL);
Insert into places (id, name, area_id, parent_id)
 Values (7, 'Kings Cross', 5, 1);
Insert into places (id, name, area_id, parent_id)
 Values (8, 'Tower of London', 5, 1);

我可以像这样独立地查询这些表：

 SELECT a.*, level FROM areas a
start with parent_id is null
connect by prior id = parent_id

SELECT p.*, level FROM places p
start with parent_id is null
connect by prior id = parent_id

有人能够告诉我将这些加入一个查询的最后一步有四个级别吗？我多年来一直在与甲骨文合作,但不知怎的,这种情况从未出现过！

如果之前在地方表中没有连接,只有一个具有地区ID的城市列表,这会更容易吗？

谢谢

最佳答案 这是你需要的吗？

with src as (
  select 'A' type, a.id, a.name, a.parent_id, null area_id from areas a
  union all
  select 'P', -p.id id, p.name, -p.parent_id parent_id, area_id from places p)
select 
  src.*, level
from 
  src
start with 
  type = 'A' and parent_id is null
connect by 
  parent_id = prior id or 
  parent_id is null and area_id = prior id
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