在boost python中腌制一个向量？

2019年8月4日 213次阅读

我有这个简单的C代码：

class Contained {};

class CannotPickle {
public:
    CannotPickle() {};
    CannotPickle(std::vector<boost::shared_ptr<Contained>> new_vector) 
      : my_vector(new_vector) {};
    std::vector<boost::shared_ptr<Contained>> my_vector;
};

struct CannotPickle_pickle_suite : boost::python::pickle_suite
{
    static
    boost::python::tuple
    getinitargs(CannotPickle const& c)
    {
        return boost::python::make_tuple(c.my_vector);
    }
};

我正在尝试为CannotPickle启用这样的pickle支持：

class_<Contained>("Contained");
class_<std::vector<boost::shared_ptr<Contained>>>("ContainedPtrList")
        .def(vector_indexing_suite<std::vector<boost::shared_ptr<Contained>>, true>());
class_<CannotPickle>("CannotPickle")
        .def_pickle(CannotPickle_pickle_suite());

当我尝试在CannotPickle上实际调用pickle时,我收到此错误：
RuntimeError：未启用“MyModule.ContainedPtrList”实例的Pickling(http://www.boost.org/libs/python/doc/v2/pickle.html)

如何为vector_indexing_suite启用酸洗？

最佳答案 一些额外的搜索产生了这个代码,似乎工作：

#include <vector>

#include <boost/python.hpp>
#include <boost/python/suite/indexing/vector_indexing_suite.hpp>
#include <boost/smart_ptr.hpp>
namespace py = boost::python;

template <class C>
struct PickleSuite: public py::pickle_suite { BOOST_STATIC_ASSERT(sizeof(C)==0); };

template <typename  T>
struct PickleSuite< std::vector<T> >: public py::pickle_suite
{
    static py::tuple getinitargs(const std::vector<T>& o)
    {
        return py::make_tuple();
    }

    static py::tuple getstate(py::object obj)
    {
        const std::vector<T>& o = py::extract<const std::vector<T>&>(obj)();

        return py::make_tuple(py::list(o));
    }

    static void setstate(py::object obj, py::tuple state)
    {
        std::vector<T>& o = py::extract<std::vector<T>&>(obj)();

        py::stl_input_iterator<typename std::vector<T>::value_type> begin(state[0]), end;
        o.insert(o.begin(),begin,end);
    }
};
点赞